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Andrew [12]
3 years ago
15

Negatively charged particles within the atom are called what?

Chemistry
1 answer:
Ivahew [28]3 years ago
5 0
Negatively charged particles in atom - Electrons
You might be interested in
Changes in which two characteristics can indicate a physical change?
liberstina [14]

Answer:

A-Shape

C-state

Explanation:

reactivity and flammability are both indicators of chemicals changes

6 0
3 years ago
Read 2 more answers
Calculate the concentration of CO2 in water at 25 degrees Celsius when the pressure of CO2 over the solution is 4.5 atm. At 25 d
OLEGan [10]

Answer : The concentration of CO_2 is, 0.12 M

Explanation :

Using Henry's law :

C_{CO_2}=k_H\times p_{CO_2}

where,

C_{CO_2} = concentration of CO_2 = ?

p_{CO_2} = partial pressure of CO_2 = 4.5 atm

k_H = Henry's law constant  = 3.1\times 10^{-2}mol/L.atm

Now put all the given values in the above formula, we get:

C_{CO_2}=3.1\times 10^{-2}mol/L.atm\times (4.5atm)

C_{CO_2}=0.1395M\approx 0.12M

Thus, the concentration of CO_2 is, 0.12 M

5 0
3 years ago
Using only the 1h nmr spectrum of the crude nitration product, determine if the product is mostly ortho-, meta-, or para- substi
tatiyna
<span>The nitartion of methyl benzoate is expected to proceed as given in the equation below:

</span>

In methyl benzoate there are 3 types of 1 H proton. The two ortho to the C=O group is a doublet at 8 ppm the 2 metal to the C=O is a multiple at 7.5 ppm and one para to the C=O is a multiplet at 7.5 ppm.

On nitration the ortho will probably show two signal one being a single with 3 proton integration and one a doublet with 1 H integration

The meta will show a highly down field singlet (coresponding to 1 proton), two unequal doublets (corresponding to 1 H each) and one multiplets (corresponding to 1H). This is the major product as seen from the 1H NMR.

The para isomer will come as two doublets which will be very close to each other there is a small signal for this set between 8.2 and 8.3 ppm.

7 0
4 years ago
What is the freezing point of a solution of 465 g of sucrose c12h22o11 dissolved in 575 ml of water?
Amanda [17]

Answer:

The freezing point of the solution is - 4.39 °C.

Explanation:

We can solve this problem using the relation:

<em>ΔTf = (Kf)(m),</em>

where, ΔTf is the depression in the freezing point.

Kf is the molal freezing point depression constant of water = -1.86 °C/m,

density of water = 1 g/mL.

<em>So, the mass of 575 mL is 575 g = 0.575 kg.</em>

m is the molality of the solution (m = moles of solute / kg of solvent = (465 g / 342.3 g/mol)/(0.575 kg) = 2.36 m.

<em>∴ ΔTf = (Kf)(m</em>) = (-1.86 °C/m)(2.36 m) = <em>- 4.39 °C.</em>

<em>∵ The freezing point if water is 0.0 °C and it is depressed by - 4.39 °C.</em>

<em>∴ The freezing point of the solution is - 4.39 °C.</em>

6 0
3 years ago
What type of a reaction occurs when a sodium hydroxide solution is mixed with an acetic acid solution?
Harman [31]

Answer:

C) acid-base neutralization

Explanation:

NaOH + CH₃COOH = CH₃COONa + H₂O

Break the solutions apart:

NaOH = Na⁺ + OH⁻

CH₃COOH = CH₃COO⁻ + H⁺

Combine the resulting solution after the reaction:

OH⁻ + H⁺ = H₂O

7 0
3 years ago
Read 2 more answers
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