Solution:
a) By stoichoimetry If 6 moles of gives 4 mole of
, then 22 moles of
will give:
moles of
b) If 6 moles of reacts with one mole of
, then 22 moles of
will react :
moles of
Moles of left after the reaction =
moles.
c) 0 Moles of , since it is present in less amount it will get completely consumed in the reaction. Hence, it is limiting reagent.
Answer: Option (d) is the correct answer.
Explanation:
It is given that molecular formula is . Now, we will calculate the degree of unsaturation as follows.
Degree of unsaturation =
=
= 9 - 8 + 1
= 2
As the degree of unsaturation comes out to be 2. It means that this compound will contain one ring and one double bond.
Yes, this compound could be an alkyne as for alkyne D.B.E = 2.
But this compound cannot be a cycloalkane because for a cycloalkane D.B.E = 1 which is due to the ring only.
Thus, we can conclude that it is a cycloalkane is not a structural possibility for this hydrocarbon.
Answer:
Explanation:
Density is found by dividing the mass by the volume.
The mass of the liquid is 12.7 grams.
We know that 15 mL of this liquid was added to a 50 mL graduated cylinder. Therefore, the volume is 15 mL. The 50 mL is not relevant, it only tells us about the graduated cylinder.
Substitute the values into the formula.
Divide.
Round to the nearest hundredth. The 6 in the tenth place tells us to round the 4 to a 5.
The density of the liquid is about 0.85 grams per milliliter and choice A is correct.