All categories

3 years ago

The reaction shown below occurs in the blood between hemoglobin (Hb) and oxygen.

Chemistry

1 answer:

OlgaM077 [116]3 years ago

7 0

Answer:

A, B, C

Explanation:

Notice that this reaction involves double arrows, meaning this represents an equilibrium reaction in which we observe a forward reaction (combination of hemoglobin and oxygen) and a reverse reaction (decomposition of the oxyhemoglobin complex).

Upon inhalation of oxygen, it accesses the blood of a person and binds to hemoglobin, so the following reaction proceeds to the right.

Similarly, the opposite process takes place in muscles, oxyhemoglobin is decomposed back into hemoglobin and oxygen.

The equilibrium constant reaction is relatively high, since at standard conditions, this is a spontaneous reaction, hemoglobin combines with oxygen without any additional external source of energy.

You might be interested in

What element has the electrons configuration of [Ar]4s^2 3d^5

Scilla [17]

Answer:

Manganese

Explanation:

Using rules you will find the location on 3d^5 because you subtract one level when in the d block

5 0

3 years ago

Predict whether each of the following substances would be more soluble in water (polar solvent) or in a hydrocarbon such as hept

vlada-n [284]

Answer:

Vegetable oil will dissolve in heptane

Isopropyl alcohol will dissolve in water

Potassium Bromide will dissolve in water

Explanation:

In chemistry, like dissolves like. This implies that polar substances will dissolve in polar solvents and nonpolar substances will dissolve in nonpolar solvents. This is so because, dissolution of a solute in a solvent involves adequate intermolecular interaction between solute and solvent which isn't possible between a polar and a nonpolar substance.

5 0

3 years ago

Define and give an example of an acid and of a base.

Debora [2.8K]

A Brønsted-Lowry acid is defined as a compound that gives hydronium ions to another compound—for example, hydrochloric acid gives H+ ions to compounds it reacts with. Brønsted-Lowry bases are compounds that can accept hydronium ions—when ammonia gets a hydronium ion from HCl, it forms the ammonium ion.

5 0

3 years ago

Calculate the equilibrium constant for the reaction: 2 Cr + 3 Pb2+ ----> 3 Pb + 2 Cr3+ at 25oC. Eocell = 0.61 V

sattari [20]

Answer:

The value is $K = 8*10^{61}$

Explanation:

From the question we are told that

The equation is $2 Cr + 3Pb^{2+} \to 3Pb + 2Cr^{3+}$

The temperature is $T = 25^oC = 298 K [room \ temperature ]$

The emf at standard condition is $E^o_{cell} = 0.61 \ V$

Generally at the cathode

$3Pb^{2+}(aq) + 6 e- --> 3Pb(s)$

At the anode

$2Cr^{3+} + 6e^- \to 2Cr$

Generally for an electrochemical reaction, at room temperature the Gibbs free energy is mathematically represented as

$G = n* F * E^o_{cell}$

Here n is the no of electron with value n = 6

F is the Faraday's constant with value 96487 J/V

=> $G = 6 * 96487 * 0.61$

=> $G = 3.5 *10^{5} \ J$

This Gibbs free energy can also be represented mathematically as

$G = RTlogK$

Here R is the cell constant with value 8.314J/K

K is the equilibrium constant

From above

=> $K = antilog^{\frac{G}{ RT} }$

Generally antilog = 2.718

=> $K = 2.718^{\frac{3.5 *10^5}{ 8.314* 298} }$

=> $K = 8*10^{61}$

6 0

2 years ago

Consider the reaction: 2HI(g) ⇄ H2(g) + I2(g). It is found that, when equilibrium is reached at a certain temperature, HI is 35.

Sliva [168]

Answer:

Kc = 0.075

Explanation:

The dissociation (α) is the initial quantity that ionized divided by the total dissolved. So, let's calling x the ionized quantity, and M the initial one:

α = x/M

x = M*α

x = 0.354M

For the stoichiometry of the reaction (2:1:1), the concentration of H₂ and I₂ must be half of the acid. So the equilibrium table must be:

2HI(g) ⇄ H₂(g) + I₂(g)

M 0 0 Initial

-0.354M +0.177M +0.177M Reacts

0.646M 0.177M 0.177M Equilibrium

The equilibrium constant Kc is the multiplication of the products' concentrations (elevated by their coefficients) divided by the multiplication of the reactants' concentrations (elevated by their coefficients):

$Kc = \frac{[H2]*[I2]}{[HI]^2}$

$Kc = \frac{0.177M*0.177M}{(0.646M)^2}$

$Kc = \frac{0.03133M^2}{0.41732M^2}$

Kc = 0.075

5 0

3 years ago