Answer:
13 hz
Explanation:
Speed of sound = 1522
Dolphin swims off at 8.0 = Cs
Frequency of clicks = Fo = 2500
Fo = fs(c/c+cs)
2500 = fs(1522/1522+8)
2500 = fs(1522/1530)
2500 = 0.99477fs
Fs = 2500/0.99477
= 2513.1
From here, we find the difference between this frequency and the number of clicks per second
= 2513.1 - 2500
= 13.1 hz
Approximately 13 Hz
Answer:
θ = 33.54 rad
Explanation:
This is a circular motion exercise
θ= θ₀ + w₀ t + ½ α t²
suppose that for t = 0 the body is at its initial point θ₀ = 0 and from the graph we see that the initial angular velocity w₀ = -9.0 rad / s
we look for the angular acceleration,
α =
from the graph taken two points
α =
α = 3 rad / s²
we substitute in the first equation
θ = 0 -9 t + ½ 3 t²
the displacement is requested for t = 8.6 s
θ = = -9 8.6 + 3/2 8.6²
θ = 33.54 rad
Answer:
acceleration is the rate in which your speed increase at a constant or steady rate
Explanation:
Answer:
D) The capacitor will pull the material into the space between the plates, and the potential energy stored between the plates of the capacitor will decrease by a factor of 3
Explanation:
points to note
A) inserting a material with dielectric constant of 3 between the plates means that the capacitance C will increase by 3.
B) Since the battery is disconnected, the potential difference V between plate will not remain constant.
C) increasing the capacitance reduces the potential difference across the plate, and from C = Q/V it can be seen that the charges on the plate remains constant.
From the proof in the image below, the reduction in the potential energy of the capacitor is due to the energy used by the capacitor to pull the dielectric material into the space.
The electrostatic force between the glass bead and the plastic bead is given by:
where
k is the Coulomb's constant
q1 is the charge of the glass bead
q2 is the charge of the plastic bead
r is the separation between the two beads
In this problem,
and
, and since we know the force,
, we can rearrange the equation to find q2, the charge of the plastic bead: