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AnnZ [28]
3 years ago
8

You drop the pendulum bob and it swings from point A to point C, and then back again. Eventually it slows down and stops, settli

ng at point B. A similar pendulum can be found in a pendulum clock. However, the clock pendulum does not stop; it continues to swing back and forth, with a tick-tick. Why is there a difference between the lab pendulum and the clock pendulum?
A) All of the potential energy is not converted to kinetic energy.
B) An enclosed pendulum is not acted on by air resistance or gravity.
C) An external energy source, like a battery, is needed to maintain motion.
Eliminate
D) Air resistance is not a factor since the pendulum is housed inside the clock.
Chemistry
1 answer:
maria [59]3 years ago
6 0
B An enclosed pendulum is not acted on by air resistence or gravity. Plus, pendulum's in clocks are electronic (I think) so that's why it keeps moving back in forth. (at least i think so)

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HClO3 + NH3 Right arrow. NH4+ + ClO3– Which is a base-conjugate acid pair?
romanna [79]

Answer:

NH3 and NH4+

Explanation:

5 0
2 years ago
A force of 30 N is applied to a screwdriver to pry the lid off of a can of paint. The screwdriver applies 75 N of force to the l
Ipatiy [6.2K]
The formula of mechanical advantage in this situation is:
MA = Input Force ÷ Output Force

The input force is the 30N applied to a screwdriver while the output force is the 75N force to the lid.

So,

MA = 30N/75N
MA = 0.40

Hence the mechanical advantage of the screwdriver is 0.40.
7 0
3 years ago
Name the alkanes please help
Pie
Methane CH4 CH4 1 hexane C6H14 CH3(CH2)4CH3 5
ethane C2H6 CH3CH3 1 heptane C7H16 CH3(CH2)5CH3 9
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butane C4H10 CH3CH2CH2CH3 2 nonane C9H20 CH3(CH2)7CH3 35
pentane C5H12 CH3(CH2)3CH3 3 decane C10H22 CH3(CH2)8CH3 75
4 0
1 year ago
Separate this redox reaction into its balanced component half-reactions. What is the oxidation and reduction half reactions
erma4kov [3.2K]
<span>Separate this redox reaction into its component half-reactions. 
Cl2 + 2Na ----> 2NaCl 

reduction: Cl2 + 2 e- ----> 2Cl-1 
oxidation: 2Na ----> 2Na+ & 2 e- 


2) Write a balanced overall reaction from these unbalanced half-reactions: 

oxidation: Sn ----> Sn^2+ & 2 e- 
reduction: 2Ag^+ & 2e- ----> 2Ag 

giving us 
2Ag^+ & Sn ----> Sn^2+ & 2Ag </span>Steve O <span>· 5 years ago </span><span>
</span>
3 0
3 years ago
Read 2 more answers
15. If you dilute a 6 M solution of HCl from 5 mL to 50mL, what is the concentration of this new solution? (M1V1 = M2V2)
Andreyy89

Answer:

B) 0.6M

Explanation:

               I apologize in advance if it is not correct :l

The (M1V1= M2V2) is given for you to plug in the correct numbers so let's jot this down.

                    (M1*V1= M2*V2)

so they give us 6M which would be our (M1), from this we can also conclude that 5mL is also V1; ( if you notice the M1's and V1's are always found next to eachother). This leads us to our 50mL, this would be our V2 because the volume went from 5mL to 50mL. Now lets put this in order based on what we know.

M1= 6M                                (M1*V1= M2*V2)

V1= 5mL

M2= ?

V2= 50mL

now we plug in what we know into the equation to find the unknown (M2)

                   (6M*5mL= M2*50mL)

now we could do the long math, but I don't think your on brainly to do the hard way. so lets keep it simple!

                   We are going to put the 50mL under the (6M*5mL) for division.

                             \frac{(6M*5mL)}{(50mL)} This is honestly MUCH easier, than manually answering. you just put that in the calculator and it'll give you B) 0.6M

                 

   honestly though I might not know what I'm doing cuz im currently doing my test and decided to answer this question ;)

        Good Luck!

6 0
2 years ago
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