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3 years ago

Fill in the blank to complete the statement

Chemistry

1 answer:

max2010maxim [7]3 years ago

3 0

Answer:

I dont get it what words are we using bc I see words on the side just it doesn't make any sense

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Can someone pls help me with this pls

Slav-nsk [51]

Answer:

I would say element

Explanation:

because it is made of two different types of atoms chemically bonded together!

I'm sorry if wrong!

8 0

3 years ago

Explain how the principal of uniformitarianism is used to interpret earths past

vesna_86 [32]

Answer:

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3 0

3 years ago

The substance oxidized causes the other substance to be reduced and is called the:.

blsea [12.9K]

Answer:hydrogen Peroxide

Explanation:

4 0

3 years ago

Read 2 more answers

Sulfur reacts with fluorine to produce three different compounds. The mass ratio of fluorine to sulfur for each compound is give

NARA [144]

Answer:

Explanation:

Mass of F / Mass of S = 2.962/1 =2.962 X 32 / 32 = 94.78/32

Mass of F / Mass of S = 2.370 /1 = 2.370 X 32 / 32 = 75.84 /32

Mass of F /Mass of S = 3.555/1 = 3.555 x 32 / 32 = 113.76 / 32 .

Now constant mass of S that is 32 g reacts with different mass of F. They are as follows :

94.78 g , 75.84 g , and 113.76 g

Their ratio = 94.78 : 75.84 : 113.76

divide them by 19

their ratio = 5 : 4 : 6

So these data are consistent with law of multiple proportion.

8 0

3 years ago

When 7.085 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 21.71 grams of CO2 and 10.37 grams of H

Taya2010 [7]

Answer:

- Empirical:

$C_3H_7$

- Molecular:

$C_6H_{14}$

Explanation:

Hello,

In this case, based on the information regarding the combustion, the moles of carbon turn out:

$n_C=21.71gCO_2*\frac{1molCO_2}{44gCO_2}*\frac{1molC}{1molCO_2}=0.493molC$

Moreover, the moles of hydrogen:

$n_H=10.37gH_2O*\frac{1molH_2O}{18gH_2O}*\frac{2molH}{1molH_2O}=1.152molH$

Thus, the subscripts of carbon and hydrogen in the hydrocarbon turn out:

$C=\frac{0.4934}{0.4934}=1\\H=\frac{1.15222}{0.4934}=2.335\\CH_{2.335}$

Now, looking for a suitable whole number we obtain the following empirical formula as 2.335 times 3 is 7 for hydrogen:

$C_3H_7$

In such a way, that compound has a molar mass of 43 g/mol, thus, the whole compound's molar mass is 86.18 g/mol for which the molecular formula is twice the empirical one, therefore:

$C_6H_{14}$

Which is hexane.

Best regards.

6 0

3 years ago