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Dafna11 [192]
3 years ago
7

Write a balanced equation for the dissolution of sodium carbonate (Na2CO3) in water. Find the number of moles of Na+ produced wh

en 0.207 mol of sodium carbonate dissolves.
Chemistry
1 answer:
DochEvi [55]3 years ago
4 0

Answer:

in the presence of water H2O

Na2CO3 (S) --> 2Na+ (aq)+ (CO3)2-(aq)

One mole of sodium carbonate produces two moles of Na+ ions

Therefore 0.207 moles produces 0.414 moles of Na+ ions

= 0.414 moles of Na+ ions

Explanation:

In water

Na2CO3 --> 2Na+ (aq)+ (CO3)2-(aq)

In a limited reaction, the carbonate ion reacts with the water molecules as follows

(CO3)2-(aq) + H2O←→HCO3-(aq) + OH-(aq)

sodium carbonate or soda ash dissolves in water to give 2 sodium cations and one carbonate anion

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<em />

Replacing:

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