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Alika [10]
3 years ago
9

Work out the empirical formula of a compound that contains 35% of nitrogen , 5% of hydrogen and 60% of oxygen.

Chemistry
1 answer:
Stells [14]3 years ago
3 0

Answer:

H_5N_5O_6

Explanation:

Hello there!

In this case, for the determination of empirical formulas, it is firstly necessary to assume the given percentages of the constituent atoms as the masses so we can compute their moles in the formula:

n_N=\frac{35gN}{14.01g/mol} =2.5molN\\\\n_H=\frac{5g}{1.01 g/mol}=5molH\\\\n_O=\frac{60g}{16 g/mol}  =3molO

Thus, we need to divide the resulting moles, by the fewest ones (those of nitrogen) in order to determine the coefficients in the formula:

N:\frac{2.5}{2.5}=1\\\\H:\frac{5}{2.5}=2\\\\O:\frac{3}{2.5} =1.2

However, we need to turn all these numbers, whole numbers, so we multiply by 5 to get:

H_5N_5O_6

Best regards!

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Answer:

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Explanation:

Hello,

In this case, the combustion of methane is shown below:

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PV=nRT\\\\V=\frac{nRT}{P}=\frac{1122.6mol*0.082\frac{atm*L}{mol*K}*298K}{0.98atm}\\\\V=27992L=28.00m^3

Best regards.

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