Answer:
The acceleration of the horse during this time interval is 24.286 m/min²
Explanation:
Given;
initial velocity of the horse during the gallop, u = 543 m /min
final velocity of the horse during the gallop, v = 628 m /min
time of motion, t = 3.5 minutes
The acceleration of the horse is given by the change in velocity per change in time;
Therefore, the acceleration of the horse during this time interval is 24.286 m/min²
Answer:
in order to find the average velocity use change in Displacement / change in time?
Explanation:
Answer:
The net force is 392N, pointing down.
Explanation:
The net force is the sum of all forces acting on the rock, namely the gravity ("+" acting downward) and the friction force due to air resistance ("-" acting upward):
The net force is 392N and pointing down (positive)/
Answer:
2 m/s^2
Explanation:
from the question
v=15 m/s
t=7.5
a=?
from the first equation of motion
v=u+at
where,
v=final velocity
u=initial velocity
a=acceleration
t=time
from the question (u) will be zero because the body started at rest
v=u+at
15=(0)+a×7.5
15=7.5a
a=15/7.5
a=2 m/s^2
The mass of Laura and the sled combined is 887.5 kg
