Answer:
Explanation:
conservation of momentum
initial momentum is zero
Lets say that m₁ moves along the x axis
and m₂ moves along the y axis
in the y direction
0 = m₁(0) + m₂(30) + m₃(vy)
0 = m₁(0) + m₂(30) + 3m₂(vy)
-3m₂(vy) = m₂(30)
vy = -10 m/s
in the x direction
0 = m₁(30) + m₂(0) + m₃(vx)
0 = 2m₂(30) + m₂(0) + 3m₂(vx)
-3m₂(vx) = 2m₂(30)
vx = -20 m/s
v = √(-10² + -20²) = 10√5 m/s ≈ 22.36 m/s
θ = arctan(-10/-20) = 206.56505... ≈ 206.6° CCW from the + x axis
The average dissipated power in a resistor in a ac circuit is:

where R is the resistance, and

is the root mean square current, defined as

where

is the peak value of the current. Substituting the second formula into the first one, we find

and if we re-arrange this formula and use the data of the problem, we can find the value of the peak current I0:
Commercial airliners encounter very little turbulence above 25,000 feet because the air is so thin at altitudes above 25,000 feet that turbulence has much less effect. That is option A.
<h3>What is turbulence?</h3>
A turbulence is a sudden disturbance that an airline encounters when it hits a strong wind current that can push or pull the plane.
The depth at which the airline flies determines whether the turbulence will have little or more effects on it.
At altitudes above 25,000 feet the air is so thin and light than below 25,000 feet therefore, the airline will encounter little turbulence effect.
Learn more about turbulence here:
brainly.com/question/20389242
#SPJ1
Explanation:
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