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Mashutka [201]
3 years ago
6

Atorvastatin is sold under the trade name Lipitor and is used for lowering cholesterol. Annual global sales of this compound exc

eed $13 billion. Assign a configuration to each chiral center in atorvastatin: In the boxes below, first input the numbers corresponding to the chiral centers in numerical order as a comma separated list (e.g., "1,3,4"). Then input the configurations of the chiral centers in the same order and format (e.g., "R,S,S"). chiral center(s): Configuration(s):

Chemistry
1 answer:
kotegsom [21]3 years ago
4 0

Answer:

Atorvastatin has two chiral centers. The question doesn't include the box where have to answer but I can show you in an image where are located and their configuration.

Explanation:

The first image shows the chemical structure of atorvastatin and their chiral centers identified as 1 and 2 respectively.

The second image shows the Fischer projections corresponding to every chiral carbon 1 and 2. I wrote R so suggest that there are more carbon atoms forward but not only corresponds to carbon atoms.

You can see that the chiral carbon 1 has R configuration due to the direction from the main substituent to the second follow the clockwise.

The chiral carbon 2 has S configuration due to the direction from the main substituent to the second one go anticlockwise.

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Explanation:according to question:

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3 years ago
(4) Calculate the % of a compound that can be removed from liquid phase 1 by using ONE to FOUR extractions with a liquid phase 2
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Answer:

One extraction: 50%

Two extractions: 75%

Three extractions: 87.5%

Four extractions: 93.75%

Explanation:

The following equation relates the fraction q of the compound left in volume V₁ of phase 1 that is extracted n times with volume V₂.

qⁿ = (V₁/(V₁ + KV₂))ⁿ

We also know that V₂ = 1/2(V₁) and K = 2, so these expressions can be substituted into the above equation:

qⁿ = (V₁/(V₁ + 2(1/2V₁))ⁿ = (V₁/(V₁ + V₁))ⁿ =  (V₁/(2V₁))ⁿ = (1/2)ⁿ

When n = 1, q = 1/2, so the fraction removed from phase 1 is also 1/2, or 50%.

When n = 2, q = (1/2)² = 1/4, so the fraction removed from phase 1 is (1 - 1/4) = 3/4 or 75%.

When n = 3, q = (1/2)³ = 1/8, so the fraction removed from phase 1 is (1 - 1/8) = 7/8 or 87.5%.

When n = 4, q = (1/2)⁴ = 1/16, so the fraction removed from phase 1 is (1 - 1/16) = 15/16 or 93.75%.

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Answer:

Contents Home Courses University of California Davis UCD Chem 2C: General Chemistry III UCD Chem 2C: Larsen Text Unit 4: Chemical Kinetics Expand/collapse global location

4.7: Collision Theory

Last updatedSep 3, 2020

4.6: Using Graphs to Determine (Integrated) Rate Laws

4.8: Temperature and Rate

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Learning Objectives

Molecules must collide in order to react.

In order to effectively initiate a reaction, collisions must be sufficiently energetic (kinetic energy) to break chemical bonds; this energy is known as the activation energy.

As the temperature rises, molecules move faster and collide more vigorously, greatly increasing the likelihood of bond breakage upon collision.

Collision theory explains why different reactions occur at different rates, and suggests ways to change the rate of a reaction. Collision theory states that for a chemical reaction to occur, the reacting particles must collide with one another. The rate of the reaction depends on the frequency of collisions. The theory also tells us that reacting particles often collide without reacting. For collisions to be successful, reacting particles must (1) collide with (2) sufficient energy, and (3) with the proper orientation.

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