Set up the problem with the conversion rates as fractions where when you multiply the units cancel out leaving the desired units behind.
Sometimes tectonic forces cause cracks to form in rock. If pieces of the rock move along these cracks, the cracks are called fau
1 answer:
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a) 30.0 cm
For any mirror, the radius of curvature is twice the focal length:
r = 2f
where
r is the radius of curvature
f is the focal length
For the mirror in this problem, we have
r = 60.0 cm is the radius of curvature
Therefore, solving the equation above for f, we find its focal length:
b) 90 cm
The mirror equation is:
where
s' is the distance of the image from the mirror
f is the focal length
s is the distance of the object from the mirror
For the situation in the problem, we have
f = +30.0 cm is the focal length (positive for a concave mirror)
s = 45.0 cm is the object distance from the mirror
Solving the formula for s', we find
c) -2
The magnification of the mirror is given by
where in this problem we have
s' = 90 cm is the image distance
s = 45.0 cm is the object distance
Solving the equation, we find:
So, the magnification is -2.
d) -12.0 cm
The magnification can also be rewritten as
where
y' is the height of the image
y is the heigth of the object
In this problem, we know
y = 6.0 cm is the height of the object
M = -2 is the magnification
Solving the equation for y', we find
and the negative sign means that the image is inverted.
Part e and f are exactly identical as part b) and c).