Answer:
Mass of the planet = 6.0 ×
Explanation:
Time period = 2π (R + h) / v
Orbital speed (v) = √GM / (R + h)
T² = 4π² (R + h)² / (GM/ (R + h))
= 4π² (R + h)³ / GM
making m the subject of the formula
m = 4π² (R + h)³ / GT²
= 4π² ( 6.38 × + 230 × 10³ )³ / ( 6.67 ×
) × (89 × 60)²
= 4π² ( 6610000)³ / ( 6.67 × ) × (89 × 60)²
= 5.99 ×
= 6.0 ×
Answer:
The time taken is
Explanation:
From the question we are told that
The speed of first car is
The speed of second car is
The initial distance of separation is
The distance covered by first car is mathematically represented as
Here is the initial distance which is 0 m/s
and is the final distance covered which is evaluated as
So
The distance covered by second car is mathematically represented as
Here is the initial distance which is 119 m
and is the final distance covered which is evaluated as
Given that the two car are now in the same position we have that