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AveGali [126]
3 years ago
7

4a. If a team pulls with a combined force of 9,000 N on an airplane with a mass of

Physics
1 answer:
777dan777 [17]3 years ago
7 0

Answer:

a=0.3m/s^2

Explanation:

Newton's 2nd law:

F=m*a

9000N=30000kg*a

9000N/30000kg = 30000kg*a/30000kg

0.3=a

so a=0.3m/s^2

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What is the acceleration of a proton moving with a speed of 6.5 m/s at right angles to a magnetic field of 1.5 T?
Brilliant_brown [7]

Answer:

The acceleration of the proton is 9.353 x 10⁸ m/s²

Explanation:

Given;

speed of the proton, u =  6.5 m/s

magnetic field strength, B = 1.5 T

The force of the proton is given by;

F = ma = qvB(sin90°)

ma = qvB

where;

m is mass of the proton, = 1.67 x 10⁻²⁷ kg

charge of the proton, q = 1.602 x 10⁻¹⁹ C

The acceleration of the proton is given by;

a = \frac{qvB}{m}\\\\a = \frac{(1.602*10^{-19})(6.5)(1.5)}{1.67*10^{-27}}\\\\a = 9.353*10^8 \ m/s^2

Therefore, the acceleration of the proton is 9.353 x 10⁸ m/s²

4 0
3 years ago
A 1350 kg uniform boom is supported by a cable. The length of the boom is l. The cable is connected 1/4 the
olchik [2.2K]

Answer:

Tension= 21,900N

Components of Normal force

Fnx= 17900N

Fny= 22700N

FN= 28900N

Explanation:

Tension in the cable is calculated by:

Etorque= -FBcostheta(1/2L)+FT(3/4L)-FWcostheta(L)= I&=0 static equilibrium

FTorque(3/4L)= FBcostheta(1/2L)+ FWcostheta(L)

Ftorque=(Fcostheta(1/2L)+FWcosL)/(3/4L)

Ftorque= 2/3FBcostheta+ 4/3FWcostheta

Ftorque=2/3(1350)(9.81)cos55° + 2/3(2250)(9.81)cos 55°

Ftorque= 21900N

b) components of Normal force

Efx=FNx-FTcos(90-theta)=0 static equilibrium

Fnx=21900cos(90-55)=17900N

Fy=FNy+ FTsin(90-theta)-FB-FW=0

FNy= -FTsin(90-55)+FB+FW

FNy= -21900sin(35)+(1350+2250)×9.81=22700N

The Normal force

FN=sqrt(17900^2+22700^2)

FN= 28.900N

4 0
3 years ago
What is a difference between physical traits and personality traits?
malfutka [58]

Answer:

A physical trait is visible to the naked eye, such as, having six fingers; and a character trait is invisible to the naked eye, such as, being charming. Both can be subjective, for instance, claiming somebody has a big nose is a subjective comment about somebody's physical appearance.

5 0
3 years ago
Read 2 more answers
The atmosphere of Jupiter is essentially made up of hydrogen, H2. For H2, the specific gas constant is 4157 J/(kg K). The accele
Alenkinab [10]

Answer:

h=17357.9m

Explanation:

The atmospheric pressure is just related to the weight of an arbitrary column of gas in the atmosphere above a given area. So, if you are higher in the atmosphere less gass will be over you, which means you are bearing less gas and the pressure is less.

To calculate this, you need to use the barometric formula:

P=P_0e^{-\frac{Mg}{RT}h}

Where R is the gas constant, M the molar mass of the gas, g the acceleration of gravity, T the temperature and h the height.

Furthermore, the specific gas constant is defined by:

R_{H_2}=\frac{R}{M}

Therefore yo can write the barometric formula as:

P=P_0e^{-\frac{g}{R_{H_2}T}h}

at the surface of the planet (h =0) the pressure is P_0[\tex]. The pressure at the height requested is half of that:[tex]P=\frac{P_0}{2}

applying to the previuos equation:

\frac{P_0}{2} =P_0e^{-\frac{g}{R_{H_2}T}h}

solving for h:

h=17357.9m

3 0
3 years ago
How fast is a 90kg man running if his kinetic energy is 720 J?
zheka24 [161]
Answer:
4 m/s
Explanation:
KE=1/2mv^2
720=1/2(90)
720=45v^2
divide by 45
16= v^2
over the square root
4=v
v= 4m/s
6 0
3 years ago
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