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arlik [135]
3 years ago
7

9) What will happen to the period of a pendulum if we change the rope of a pendulum with another which is four times with the in

itial? B. halved A. double C. tripled D increase four times .​
Physics
1 answer:
Arturiano [62]3 years ago
5 0

Double

Explanation:

Since the period T of a pendulum is given by

T = 2\pi \sqrt{\dfrac{l}{g}}

By increasing the length of the pendulum by 4, the period becomes

T' = 2\pi \sqrt{\dfrac{4l}{g}} = 2\left(2\pi \sqrt{\dfrac{l}{g}}\right) = 2T

You can see that the period doubles when we increase the length by a factor of 4.

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A mass on a spring with k=88.7 N/m oscillates 15 times in 9.24s. what is the objects mass? unit=kg?
sweet [91]

The mass on the spring is 0.86 kg

Explanation:

The period of a mass-spring system is given by the equation

T=2\pi \sqrt{\frac{m}{k}}

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In this problem, we have:

k = 88.7 N/m is the spring constant

The system makes 15 oscillations in 9.24 s: therefore, the period of the system is

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Now we can re-arrange the first equation  to solve for the mass:

m=k(\frac{T}{2\pi})^2=(88.7)(\frac{0.62}{2\pi})^2=0.86 kg

Learn more about period:

brainly.com/question/5438962

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