Trình bày sự hình thành phân tử CCl4 (lai hoá sp3)

Working on-board a research vessel somewhere at sea, you have (carefully) isolated 12.5 micrograms (12.5 ×10–6 g) of what you ho

german

Answer:

The value is $Z = 311.33 \ g/mol$

Explanation:

From the question we are told that

The mass of saxitoxin is $m = 12.5 mg = 12.5 * 10^{-6} g$

The volume of water is $V = 3.10 mL = 3.10 *10^{-3} L$

The osmotic pressure is $P = 0.236 = \frac{0.236}{760} = 3.105 * 10^{-4} atm$

The temperature is $T = 19^oC = 19 + 273 = 292 \ K$

Generally the osmotic pressure is mathematically represented as

$P = C * T * R$

Here R is the gas constant with value

$R = 0.0821 ( L .atm /mol. K)$

and C is the concentration of saxitoxin

So

$3.105 * 10^{-4} = C * 0.0821 * 292$

$C = 1.295 *10^{-5} mol/L$

Generally the number of moles of saxitoxin is mathematically represented as

$n = C * V$

=> $n = 1.295 *10^{-5} *3.10 *10^{-3}$

=> $n = 4.015 *10^{-8} \ mol$

Generally the molar mass of saxitoxin is mathematically represented as

$Z = \frac{m}{n}$

=> $Z = \frac{12.5 * 10^{-6}}{ 4.015 *10^{-8}}$

=> $Z = 311.33 \ g/mol$

5 0

4 years ago

Think about a wooden chair and a balloo. What do these two objects always have in common

vovangra [49]

A. Both are made of atoms.

5 0

4 years ago

Read 2 more answers

Which of the following can explain the daily change in sea level observed along a coast?

Paul [167]

The answer is: <span>A.The gravitational pull of the moon on the water near the coast </span>

4 0

3 years ago

4 moles of monoatomic ideal gas is compressed adiabatically causing the temperature to increase from 300 K to 400 K. Calculate t

yawa3891 [41]

Answer:

the work done on the gas is 4,988.7 J.

Explanation:

Given;

number of moles of the monoatomic gas, n = 4 moles

initial temperature of the gas, T₁ = 300 K

final temperature of the gas, T₂ = 400 K

The work done on the gas is calculated as;

$W = \Delta U = nC_v(T_2 -T_1)$

For monoatomic ideal gas: $C_v = \frac{3}{2} R$

$W = \frac{3}{2} R \times n(T_2-T_1)$

Where;

R is ideal gas constant = 8.3145 J/K.mol

$W = \frac{3}{2} R \times n(T_2-T_1) \\\\W = \frac{3}{2} (8.3145) \times 4(400-300) \\\\W = \frac{3}{2} (8.3145) \times 4(100)\\\\W = 4,988.7 \ J$

Therefore, the work done on the gas is 4,988.7 J.

4 0

3 years ago

What is the formula for potassium citrate and how do you find it?

oee [108]

Answer:

Potassium citrate (also known as tripotassium citrate) is a potassium salt of citric acid with the molecular formula K3C6H5O7.

Chemical formula: K3C6H5O7

Density: 1.98 g/cm3

Melting point: 180 °C (356 °F; 453 K)

Boiling point: 230 °C (446 °F; 503 K)

Explanation:

7 0

3 years ago

Read 2 more answers