When plug prongs are connected to the metal case of an appliance, a part that should always be placed next to the case is a

1 answer:

6 0

The correct answer is (d.) mica washer. When a plug prongs are connected to the metal case of an appliance, a part that should always be placed next to the case is a mica washer. Mica washer are used as a window for any radiation detectors.

You might be interested in

An object starts at rest and accelerates at a rate of 4 m/s squared, how far does travel after 10 seconds

GenaCL600 [577]

40m/s2 because its already traveling 4m/s soo in 10 second it will be at 40 miles per seconds
4*10
=40

4 0

3 years ago

What does the "coefficient of friction" tell you?

Arte-miy333 [17]

a coefficient of fraction is a value that shows the relationship between two objects and the normal reaction between the objects that are involved.

8 0

3 years ago

What is the answer to this question

leva [86]

The answer is A 0 degrees is the freezing point of water

Plz mark brainliest

7 0

3 years ago

Why is magnetic force a non contact force?

lianna [129]

Bcoz when you place a magnet close enough the magnet attracts or repals without any other fore we dont touch the magnet so it is non contact

6 0

3 years ago

A non uniform rod has mass

Doss [256]

Answer:

$r_{cm} = L/3$

Explanation:

Mass: M, Length: L.

$\sigma (x) = b(L-x)$

The formula that gives center of mass is

$\vec{r}_{cm} = \frac{m_1\vec{r}_1 + m_2\vec{r}_2 + ...}{m_1 + m_2 + ...} = \frac{\Sigma m_i \vec{r}_i}{\Sigma m_i}$

In the case of a non-uniform mass density, this formula converts to

$\vec{r}_{cm} = \frac{\int\limits^L_0 {x\sigma(x)} \, dx }{\int\limits^L_0 {\sigma(x)} \, dx }$

where the denominator is the total mass and the nominator is the mass times position of each point on the rod.

We have to integrate the mass density over the total rod in order to find the total mass. Likewise, we have to integrate the center of mass of each point (xσ(x)) over the total rod. And if we divide the integrated center of mass to the total mass, we find the center of mass of the rod:

$\vec{r}_{cm} = \frac{\int\limits^L_0 {x\sigma(x)} \, dx }{\int\limits^L_0 {\sigma(x)} \, dx } = \frac{\int\limits^L_0 {xb(L-x)} \, dx }{\int\limits^L_0 {b(L-x)} \, dx } = \frac{b\int\limits^L_0{(xL - x^2)} \, dx }{b\int\limits^L_0 {(L-x)} \, dx } = \frac{\frac{x^2L}{2} - \frac{x^3}{3}}{Lx - \frac{x^2}{2}}\left \{ {{x=L} \atop {x=0}} \right.$

Here x's are cancelled. Otherwise, the denominator would be zero.

$r_{cm} = \frac{\frac{xL}{2}-\frac{x^2}{3}}{L-\frac{x}{2}}\left \{ {{x=L} \atop {x=0}} \right. = \frac{\frac{L^2}{2}-\frac{L^2}{3}}{L-\frac{L}{2}} = \frac{\frac{L^2}{6}}{\frac{L}{2}} = \frac{L}{3}$

8 0

3 years ago