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3 years ago

When plug prongs are connected to the metal case of an appliance, a part that should always be placed next to the case is a

1 answer:

6 0

The correct answer is (d.) mica washer. When a plug prongs are connected to the metal case of an appliance, a part that should always be placed next to the case is a mica washer. Mica washer are used as a window for any radiation detectors.

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The floor of a railroad flatcar is loaded with loose crates having a coefficient of static friction of 0.420 with the floor. If

bonufazy [111]

Answer:

The distance is $s= 30.3 \ m$

Explanation:

From the question we are told that

The coefficient of static friction is $\mu_s = 0.42$

The initial speed of the train is $u = 57 \ km /hr = 15.8 \ m/s$

For the crate not to slide the friction force must be equal to the force acting on the train i.e

$-F_f = F$

The negative sign shows that the two forces are acting in opposite direction

=> $mg * \mu_s = ma$

=> $-g * \mu_s = a$

=> $a = -9.8 * 0.420$

=> $a = -4.116 m/s^2$

From equation of motion

$v^2 = u^2 + 2as$

Here v = 0 m/s since it came to a stop

=> $s= \frac{v^2 - u^2 }{ 2 a}$

=> $s= \frac{0 -(15.8)^2 }{ - 2 * 4.116}$

=> $s= 30.3 \ m$

7 0

3 years ago

PLZ HELP!! List properties of ions.

Andreas93 [3]

Ionic compounds typically have high melting and boiling points, and are hard and brittle. when melted or dissolved they become highly conductive, because the ions are mobilized.

3 0

3 years ago

If a proton were released from rest at the sphere's surface, what would be its speed far from the sphere?

balu736 [363]

Let the sphere is having charge Q and radius R

Now if the proton is released from rest

By energy conservation we can say

$U = K$

$\frac{kQe}{R} = \frac{1}{2}mv^2$

$\frac{2kQe}{mR} = v^2$

now take square root of both sides

$v =\sqrt{\frac{2kQe}{mR}}$

so the proton will move by above speed and

here Q = charge on the sphere

R = radius of sphere

$k = 9 * 10^9$

5 0

3 years ago

Read 2 more answers

The acceleration due to gravity on the moon is about 1/6 of the acceleration due to gravity on the earth. A net force F acts hor

uysha [10]

Answer:

c. $a_m$

Explanation:

We are given that

Acceleration due to gravity on the moon= $a_m$

Acceleration due to gravity on the earth= $a_e$

$g_m=\frac{1}{6}g_e$

Net force due to am on an object on moon= $F_{net}=ma_m$

There is no friction and no drag force and there is no gravity involved

Then, the force acting on an object on earth= $F=ma_e$

$F=F_{net}$ (given)

$ma_m=ma_e$

$a_e=a_m$

Hence, option c is true.

3 0

3 years ago

A fountain sends a stream of water straight up into the air to a maximum height of 5.60 m. The effective area of the pipe feedin

kifflom [539]

Answer:It increases confidence because the more times you conduct the same experiment over and over should either prove your hypothesis right and wrong and eliminate any random occurrences that might affect your results.

Read more on Brainly.com - brainly.com/question/1492542#readmore

Explanation:

5 0

3 years ago