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3 years ago

When plug prongs are connected to the metal case of an appliance, a part that should always be placed next to the case is a

1 answer:

6 0

The correct answer is (d.) mica washer. When a plug prongs are connected to the metal case of an appliance, a part that should always be placed next to the case is a mica washer. Mica washer are used as a window for any radiation detectors.

You might be interested in

What is the kinetic energy of a 2,000-kg boat moving at 5.0 m/s?

vlada-n [284]

Answer:

25kJ

Explanation:

K = 1/2 mv^2 = 1/2 x 2000kg x (5.0m/s)^2

= 25 x 10^3 J = 25kJ

6 0

3 years ago

How many centimeters are in 3.50 feet?

Kazeer [188]

106.68 centimetres are in 3.50 feet

4 0

3 years ago

You're driving down the highway late one night at 20 m/s when a deer steps onto the road 44 m in front of you. Your reaction tim

never [62]

Answer:

14.0 m

25.1 m/s

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

Distance traveled in the reaction time

Distance = Speed × Time

$\text{Distance}=20\times 0.5=10\ m$

$v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{0^2-20^2}{2\times -10}\\\Rightarrow s=20\ m$

Distance in which the car will stop is 10+20 = 30.0 m

So, the car will not hit the deer

Distance between the car and deer is 44-30 = 14.0 m

$\text{Distance}=u\times 0.5=0.5u\ m$

$v^2-u^2=2as\\\Rightarrow -u^2=2as-v^2\\\Rightarrow u^2=v^2-2as\\\Rightarrow u^2=0^2-2\times -10\times (44-0.5u)\\\Rightarrow u^2=20(44-0.5u)\\\Rightarrow u^2=880-10u\\\Rightarrow u^2+10u-880=0$

$u=\frac{-10+\sqrt{10^2-4\cdot \:1\left(-880\right)}}{2\cdot \:1}, u=\frac{-10-\sqrt{10^2-4\cdot \:1\left(-880\right)}}{2\cdot \:1}\\\Rightarrow u=25.08, -35.08\ m/s$

Maximum speed of the car by which it will not hit the deer is 25.1 m/s

5 0

3 years ago

Read 2 more answers

A driver notices that her 1280 kg car slows down from 92 km/h to 68 km/h in about 7.5 s on the level when it is in neutral. Appr

sweet-ann [11.9K]

Answer:

P = 25299.75 watts

Since 80km/h is the average speed of 92km/h and 68km/h, the power (in watts) is needed to keep the car traveling at a constant 80 km/h is P = 25299.75 watts

Explanation:

Given;

Mass of car m = 1280kg

initial speed v1 = 92km/h = 92×1000/3600 m/s= 25.56m/s

Final speed v2 = 68km/h = 68×1000/3600 m/s= 18.89m/s

time taken t = 7.5s

Change in the kinetic energy of the car within that period;

∆K.E = 1/2 ×mv1^2 - 1/2 × mv2^2

∆K.E = 0.5m(v1^2 -v2^2)

Substituting the values, we have;

∆K.E = 0.5×1280(25.56^2 - 18.89^2)

∆K.E = 189748.16J

Power used during this Change;

Power P = ∆K.E/t

Substituting the values;

P = 189748.16/7.5

P = 25299.75 watts

Since 80km/h is the average speed of 92km/h and 68km/h, the power (in watts) is needed to keep the car traveling at a constant 80 km/h is P = 25299.75 watts

7 0

3 years ago

the decimal reduction time (DRT) is the time it takes to kill 90% of cells present. Assume that a DRT value for autoclaving a cu

kotegsom [21]

Answer:

It takes 10.5 minutes to kill all the bacteria.

Only 1 cell would remain after 9 minutes.

Explanation:

It will take 1.5 minutes to kill 90% of the cells. So, after 1.5 minutes, only 10% would remain. After 3 minutes, only 1% remain. So, to figure out how long it would take to kill a million cells, we have to multiply 1 million by 0.1 repeatedly until the final value is less than 1 that is because when the value is less than 1, it means there are no more bacteria.

So:

$10^6 \times (0.1)^7$ = 0.1

So, you need 10.5 minutes of killing to kill one million cells.

Time taken= 7 x 1.5 minutes = 10.5 minutes.

After 9 minutes you would have:

$10^{6} \times (0.1)^{6}$ = 1 cell left

6 0

4 years ago