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Nezavi [6.7K]
2 years ago
9

What is technology?

Chemistry
1 answer:
ella [17]2 years ago
6 0

Something created for using science for use by society. Hence, option A is correct.

<h3>What is science?</h3>

Science is the pursuit and application of knowledge and understanding of the natural and social world following a systematic methodology based on evidence.

Technology is the use of science to provide human problem. It can be in the form of a machine, tool or equipment. As long as it involves applying a scientific process, it's technology.

Example of technology is a computer. It's used to store and process data in a faster way. Old technology also included Hammer, Saw, Grinding Machines etc.

Hence, option A is correct.

Learn more about technology here:

brainly.com/question/9171028

#SPJ1

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A sample of helium gas initially at 37.0°C, 785 torr and 2.00 L was heated to 58.0°C while the volume expanded to 3.24 L. What i
spayn [35]

Answer:

0.681 atm

Explanation:

To solve this problem, we make use of the General gas equation.

Given:

P1 = 785 torr

V1 = 2L

T1 = 37= 37 + 273.15 = 310.15K

P2 = ?

V2 = 3.24L

T2 = 58 = 58+273.15 = 331.15K

P1V1/T1 = P2V2/T2

Now, making P2 the subject of the formula,

P2 = P1V1T2/T1V2

P2 = [785 * 2 * 331.15]/[310.15 * 3.24]

P2 = 515.715 Torr

We convert this to atm: 1 torr = 0.00132 atm

515.715 Torr = 515.715 * 0.00132 = 0.681 atm

8 0
3 years ago
What is the endpoint of a titration?Select one:When there is no acid and all base.When the amount of acid and base are equal.Whe
user100 [1]

Answer:

The correct option is: When the amount of acid and base are equal

Explanation:

Titration is an analytic method that is used to determine the concentration of an<em> unknown solution</em>, called <em>titrand</em>.

In this method, standard solution of known concentration, called <em>titrant</em>, is taken in the burette and added drop-wise to the titrand solution in the flask, until the endpoint is reached.

In case of an acid-base titration, a <em>pH indicator</em> is used, which changes the color of the solution when the endpoint is reached.

<u>The </u><u>endpoint</u><u> indicates the </u><u>equivalence point</u><u> of an acid-base titration, where the </u><em><u>concentration of the acid and base is equal</u></em><u>. </u>

<u>Therefore, the </u><u>correct option</u><u> is: </u><u>When the amount of acid and base are equal</u>

3 0
3 years ago
1.00 g of a compound is combusted in oxygen and found to give 3.14g of CO2 and 1.29 g of H2O. From these data we can tell thatA.
lora16 [44]

Answer:

the compound contains C, H, and some other element of unknownidentity, so we can’t calculate the empirical formula

Explanation:

Mass of CO2 obtained = 3.14 g

Hence number of moles of CO2 = 3.14g/44.0 g = 0.0714 mol

The mass of the carbon in the sample = 0.0714 mol × 12.0g/mol = 0.857 g

Mass of H2O obtained = 1.29 g

Hence number of moles of H2O = 1.29g/18.0 g = 0.0717 mol

The mass of the carbon in the sample = 0.0717 mol × 1g/mol = 0.0717 g

% by mass of carbon = 0.857/1 ×100 = 85.7 %

% by mass of hydrogen = 0.0717/1 × 100 = 7.17%

Mass of carbon and hydrogen = 85.7 + 7.17 = 92.87 %

Hence, there must be an unidentified element that accounts for (100 - 92.87) = 7.13% of the compound.

5 0
3 years ago
Reducing the emissions of which gas will lead to reducing the greenhouse effect? A) oxygen B) nitrogen C) argon D) carbon dioxid
professor190 [17]
Ten Ways to Reduce Greenhouse Gases. Burning fossil fuels such as natural gas, coal, oil and gasoline raises the level of carbon dioxide<span> in the atmosphere, and</span>carbon dioxide<span> is a major contributor to the greenhouse effect and global warming.

Source -->https://www.google.com/search?q=Reducing+the+emissions+of+which+gas+will+lead+to+reducing+the+greenh...<--

</span>Can you help me? <span>brainly.com/question/3131429
</span>
5 0
3 years ago
Read 2 more answers
When 120 g of carbon reacts completely with 320 g of oxygen the mass of carbon dioxide formed will be?
olga2289 [7]
440 cause mass cant be created or destroyed
6 0
3 years ago
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