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Nezavi [6.7K]
2 years ago
9

What is technology?

Chemistry
1 answer:
ella [17]2 years ago
6 0

Something created for using science for use by society. Hence, option A is correct.

<h3>What is science?</h3>

Science is the pursuit and application of knowledge and understanding of the natural and social world following a systematic methodology based on evidence.

Technology is the use of science to provide human problem. It can be in the form of a machine, tool or equipment. As long as it involves applying a scientific process, it's technology.

Example of technology is a computer. It's used to store and process data in a faster way. Old technology also included Hammer, Saw, Grinding Machines etc.

Hence, option A is correct.

Learn more about technology here:

brainly.com/question/9171028

#SPJ1

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Given the following at 25C calculate delta Hf for HCN (g) at 25C. 2NH3 (g) +3O2 (g) + 2CH4 (g) ---&gt; 2HCN (g) + 6H2O (g) delta
AysviL [449]

<u>Answer:</u> The \Delta H_f for HCN (g) in the reaction is 135.1 kJ/mol.

<u>Explanation:</u>

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. The equation used to calculate enthalpy change is of a reaction is:

\Delta H_{rxn}=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)]

For the given chemical reaction:

2NH_3(g)+3O_2(g)+2CH_4(g)\rightarrow 2HCN(g)+6H_2O(g)

The equation for the enthalpy change of the above reaction is:

\Delta H_{rxn}=[(2\times \Delta H_f_{(HCN)})+(6\times \Delta H_f_{(H_2O)})]-[(2\times \Delta H_f_{(NH_3)})+(3\times \Delta H_f_{(O_2)})+(2\times \Delta H_f_{(CH_4)})]

We are given:

\Delta H_f_{(H_2O)}=-241.8kJ/mol\\\Delta H_f_{(NH_3)}=-80.3kJ/mol\\\Delta H_f_{(CH_4)}=-74.6kJ/mol\\\Delta H_f_{(O_2)}=0kJ/mol\\\Delta H_{rxn}=-870.8kJ

Putting values in above equation, we get:

-870.8=[(2\times \Delta H_f_{(HCN)})+(6\times (-241.8))]-[(2\times (-80.3))+(3\times (0))+(2\times (-74.6))]\\\\\Delta H_f_{(HCN)}=135.1kJ

Hence, the \Delta H_f for HCN (g) in the reaction is 135.1 kJ/mol.

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A cylinder is filled with 10.0L of gas and a piston is put into it. The initial pressure of the gas is measured to be 209.kPa. T
disa [49]

Answer : The final pressure of the gas will be, 26.8 kPa

Explanation :

According to the Boyle's law, the pressure of the gas is inversely proportional to the volume of the gas at constant temperature of the gas and the number of moles of gas.

P\propto \frac{1}{V}

or,

PV=k

or,

P_1V_1=P_2V_2

where,

P_1 = initial pressure of the gas = 209 kPa

P_2 = final pressure of the gas = ?

V_1 = initial volume of the gas = 10.0 L

V_2 = final volume of the gas = 78.0 L

Now put all the given values in this formula, we get the final pressure of the gas.

209kPa\times 10.0L=P_2\times 78.0L

P_2=26.8kPa

Therefore, the final pressure of the gas will be, 26.8 kPa

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