1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
drek231 [11]
3 years ago
12

A piston-cylinder chamber contains 0.1 m3 of 10 kg R-134a in a saturated liquid-vapor mixture state at 10 °C. It is heated at co

nstant temperature until the piston expands and the final volume of R-134a is 1 m3 . What is (a) the final pressure and (b) the total energy transferred to R-134a for this process?
Physics
1 answer:
vaieri [72.5K]3 years ago
6 0

Answer:

(A) 10132.5Pa

(B)531kJ of energy

Explanation:

This is an isothermal process. Assuming ideal gas behaviour then the relation P1V1 = P2V2 holds.

Given

m = 10kg = 10000g, V1 = 0.1m³, V2 = 1.0m³

P1 = 101325Pa. M = 102.03g/mol

P2 = P1 × V1 /V2 = 101325 × 0.1 / 1 = 10132.5Pa

(B) Energy is transfered by the r134a in the form of thw work done in in expansion

W = nRTIn(V2/V1)

n = m / M = 10000/102.03 = 98.01mols

W = 98.01 × 8.314 × 283 ×ln(1.0/0.1)

= 531kJ.

You might be interested in
In physics class, Carrie learns that a force, F, is equal to the mass of an object, m, times its acceleration, a. She writes the
Phantasy [73]

Answer:

2.2 m/s^2

Explanation:

Acceleration = Force / Mass

= 7.92 / 3.6 = 2.2m/s^2

Hope this help you :3

5 0
2 years ago
Read 2 more answers
The MAC is 58 inches, The CG limits are from 26% to 43% MAC. If the CG is found to be
eimsori [14]

By working with percentages, we want to see how many inches is the center of gravity out of the limits. We will find that the CG is 1.45 inches out of limits.

<h3>What are the limits?</h3>

First, we need to find the limits.

We know that the MAC is 58 inches, and the limits are from 26% to 43% MAC.

So if 58 in is the 100%, the 26% and 43% of that are:

  • 26% → (26%/100%)*58in = 0.26*58 in = 15.08 in
  • 43% → (43%/100%)*58in = 0.43*58 in = 24.94 in.

But we know that the CG is found to be 45.5% MAC, then it measures:

(45.5%/100%)*58in = 0.455*58in = 26.39 in

We need to compare it with the largest limit, so we get:

26.39 in - 24.94 in = 1.45 in

This means that the CG is 1.45 inches out of limits.

If you want to learn more about percentages, you can read:

brainly.com/question/14345924

6 0
2 years ago
Help please I do not understand
ahrayia [7]
What don’t you understand? If you haven’t uploaded anything
3 0
2 years ago
The force exerted by the wind on the sails of a sailboat is Fsail = 330 N north. The water exerts a force of Fkeel = 210 N east.
Elena L [17]

Answer:

The magnitude of the acceleration is a_r = 1.50 \ m/s^2

The direction is  \theta =  32.5 6^o north of  east

Explanation:

From the question we are told that

   The force exerted by the wind is  F_{sail} =  (330 ) \ N \ north

   The force exerted by water is  F_{keel} =  (210  ) \ N \ east

      The mass of the boat(+ crew) is  m_b  =  260  \ kg

Now Force is mathematically represented as

      F =  ma

Now the acceleration towards the north is mathematically represented as

      a_n  =  \frac{F_{sail}}{m_b}

substituting values

       a_n  =  \frac{330 }{260}

      a_n  =  1.269 \ m/s^2

Now the acceleration towards the east is mathematically represented as

       a_e = \frac{F_{keel}}{m_b }

substituting values

      a_e = \frac{210}{260}

      a_e =0.808 \ m/s^2

The resultant acceleration is  

      a_r =  \sqrt{a_e^2 + a_n^2}

substituting values

     a_r =  \sqrt{(0.808)^2 + (1.269)^2}

      a_r = 1.50 \ m/s^2

The direction with reference from the north is evaluated as

Apply SOHCAHTOA

        tan \theta =  \frac{a_e}{a_n}

       \theta = tan ^{-1} [\frac{a_e}{a_n } ]

substituting values

     \theta = tan ^{-1} [\frac{0.808}{1.269 } ]

    \theta = tan ^{-1} [0.636 ]

   \theta =  32.5 6^o

     

   

       

5 0
3 years ago
The current through a 10-ohm resistor connected to a 120-V power supply is The current through a 10-ohm resistor connected to a
Mazyrski [523]

Answer:

12 A

Explanation:

V= I * R

V/R = I

120 V /10 Ω  = 12 AMPS

7 0
1 year ago
Other questions:
  • An accelerometer is a device that uses the extension of a spring to measure acceleration in terms of Earth's gravitational accel
    13·2 answers
  • If a set of displacement vectors laid head to tail make a closed polygon, what is the resultant vector?
    8·1 answer
  • Please answer this soon.<br> Thank u.
    12·1 answer
  • Bob is pushing a box across the floor at a constant speed of 1.2 m/s, applying a horizontal force whose magnitude is 75 N. Alice
    8·1 answer
  • 1) the strength of an electromagnet can be increased by
    7·1 answer
  • What is the net force of an object with a mass of 90.0 and accelerating at 3.0 m/s
    14·1 answer
  • Which particle would have the slowest rate of deposition? A.round particle B.very large particle C.particle with sharp ends D.pa
    14·2 answers
  • What is energy and what is the formula of energy
    7·1 answer
  • A stalled car is being pushed up a hill at constant velocity by three people. The net force on the car is Group of answer choice
    8·1 answer
  • Ipaliwanag ang paggalang
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!