Answer:A uniform ladder of mass and length leans at an angle against a frictionless wall .If the coefficient of static friction between the ladder and the ground is , determine a formula for the minimum angle at which the ladder will not slip.
Explanation:A uniform ladder of mass and length leans at an angle against a frictionless wall .If the coefficient of static friction between the ladder and the ground is , determine a formula for the minimum angle at which the ladder will not slip.
Answer:
(a)
x=7.83 Kgm/s
y=5.48 Kgm/s
(b)
191.25 N
Explanation:
(a)
Change in momentum in x direction
where m is mass and v is the velocity and 
is the angle of kick
Substituting m=0.425 Kg, v=22.5m/s and 
Change in momentum in y direction
(b)
Force exerted by the player
F=mv/t where t is time
Substituting 
F=(0.425*22.5)/0.05= 191.25 N
Answer:
The velocity with which the 5.0 kg dog has to run to have the same momentum as the 30 kg pig walking at 3.0 m/s is 18 m/s
Explanation:
Given that the mass of the dog = 5.0 kg
The mass of the pig = 30 kg
The speed with which the pig is walking = 3.0 m/s
We have that linear momentum = Mass × Velocity
Therefore, the momentum of the pig, m₁ = 30 kg × 3.0 m/s = 90 kg·m/s
m₁ = 90 kg·m/s
The momentum of the dog m₂ = Mass of the dog × Velocity of the dog
Given that m₁ is to be equal to m₂, we have;
m₁ = 90 kg·m/s = m₂ = Mass of the dog × Velocity of the dog
90 kg·m/s = m₂ = 5.0 kg × Velocity of the dog
m₂ = 5.0 kg × Velocity of the dog = 90 kg·m/s
5.0 kg × Velocity of the dog = 90 kg·m/s
Velocity of the dog = 90 kg·m/s/(5.0 kg) = 18 m/s
The velocity with which the 5.0 kg dog has to run to have the same momentum as the 30 kg pig walking at 3.0 m/s = 18 m/s.
