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4 years ago

Find tje distance between the points (-10, 10) and (-4, 2).

Mathematics

1 answer:

VikaD [51]4 years ago

6 0

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

We have the points (-10, 10) and (-4, 2). Substitute:

$d=\sqrt{(-4-(-10))^2+(2-10)^2}=\sqrt{6^2+(-8)^2}=\sqrt{26+64}=\sqrt{100}=10$

<h3>Answer: d = 10</h3>

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Answer:

The diagonal is 39.54 in

Step-by-step explanation:

First we use the Pythagorean theorem to calculate the length of the diagonal of the base.

If the base measures 13 inches by 35 inches then the diagonal is:

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Now we use the Pythagorean theorem again to find the diagonal of the cube.

If the height of the box is 13 inches and the diagonal of the base is 37.34 inches then the diagonal of the cube will be

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The baton will fit in the box if it is placed in the direction of the diagonal of the cube, since:

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3 years ago

Dilate a triangle with vertices (0,0), (0,2) and (2,0) using the scale factor k=3. What is the value of the ratio (new to origin

seropon [69]

Answer:

Part a) The ratio of the perimeters is $3$

Part b) The ratio of the areas is $9$

Step-by-step explanation:

Part A) What is the value of the ratio (new to original) of the perimeters?

we know that

If two figures are similar, then the ratio of its perimeters is equal to the scale factor

Let

z-----> the scale factor

x-----> the perimeter of the new triangle

y-----> the perimeter of the original triangle

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we have

$z=3$

substitute

$\frac{x}{y}=3$

Part B) What is the value of the ratio (new to original) of the areas?

we know that

If two figures are similar, then the ratio of its areas is equal to the scale factor squared

Let

z-----> the scale factor

x-----> the area of the new triangle

y-----> the area of the original triangle

$z^{2}=\frac{x}{y}$

we have

$z=3$

substitute

$\frac{x}{y}=3^{2}$

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