The time it takes the Polonium-194 to decay to 1/16 of its original amount is 2.8 seconds.
<h3>What is half-life?</h3>
half-life, in radioactivity, the interval of time required for one-half of the atomic nuclei of a radioactive sample to decay
To calculate the time it takes the sample of Polonium-196 to decay to 1/16 of its original amount, we use the formula below
Formula:
- = R/R'......... Equation 1
Where:
- n = Total number of time it takes Polonium-194 to decay to 1/16 of its original amount
- t = Half-life of Polonium-194
- R = Original amount of Polonium-194
- R' = Amount of Polonium-194 after decay
From the question,
Given:
Substitute these values into equation 1 and solve for n
Equating the base,
- n/0.7 = 4
- n = 0.7×4
- n = 2.8 seconds.
Hence, the time it takes the Polonium-194 to decay is 2.8 seconds.
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Answer:
We have the output force (3000) and the mechanical advantage is 15, the formula is Ma = F(o) / F(i), so 15 = 3000 / x, so x = 200 newtons!
Answer:
Explanation:
1 ha = 10⁴ m²
1375 ha = 1375 x 10⁴ m² = 13.75 x 10⁶ m²
In flow in a month = .5 x 10⁶ x 30 m³ = 15 x 10⁶ m³
Net inflow after all loss = 18.5 - 9.5 - 2.5 cm = 6.5 cm = .065 m
Net inflow in volume = 13.75 x 10⁶ x .065 m³= .89375 x 10⁶ m³
Let Q be the withdrawal in m³
Q - 15 x 10⁶ - .89375 x 10⁶ = 13.75 x 10⁶ x .75 = 10.3125 x 10⁶
Q = 26.20 x 10⁶ m³
rate of withdrawal per second
= 26.20 x 10⁶ / 30 x 24 x 60 x 60
= 26.20 x 10⁶ / 2.592 x 10⁶
= 10.11 m³ / s
Answer: 40 N
Explanation: Use the formula
F = m a
to solve this.
F = (8 kg) (5 m/s²)
F = 40 kgm/s²
F = 40 N