3 years ago

What atmospheric gas is common in the outer planets but rare in the inner planets

Physics

1 answer:

Degger [83]3 years ago

3 0

Answer:

hydrogen

Explanation:

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Find a unit vector normal to the plane containing Bold u equals 2 Bold i minus Bold j minus 3 Bold k and Bold v equals negative

Nastasia [14]

Answer:

$\hat{w}=\dfrac{\vec{5i+13j-k}}{13.92}$

Explanation:

It is given that,

$\vec{u}=2i-j-3k$

$\vec{v}=-3i+j-2k$

Taking the cross product of v and v such that,

$\vec{w}=u\times v$

$\vec{w}=(2i-j-3k)\times (-3i+j-2k)$

$\vec{w}=5i+13j-k$

$|w|=\sqrt{5^2+13^2(-1)^2}$

|w| = 13.92

Let $\hat{w}$ is the unit vector normal to the plane containing u and v. So,

$\hat{w}=\dfrac{\vec{w}}{|w|}$

$\hat{w}=\dfrac{\vec{5i+13j-k}}{13.92}$

Hence, this is the required solution.

7 0

3 years ago

Determine the displacement and distance covered by a man if he walks 10 m north, turns east and walks 20 m, and then turns right

NemiM [27]

Answer:

20m

Explanation:

The two tens cancel each other out, as they are in opposite directions. Now we only care about the 20m, which if we have no 10's, will end up 20m away.

7 0

2 years ago

The rocky planets are made of material that is much (mire/less) dense than the outer planets.

IRINA_888 [86]

The outer planets (Jupiter, Saturn, Uranus, Neptune) are called the "<u>GAS</u> giants".

The rocky planets are called "rocky" because they're made of <u>ROCK</u>.

Does this help guide you to the correct choice ?

Here's another hint: The MOST dense planet in our solar system, the one we call "Earth", is one of the 'rocky planets'.

7 0

3 years ago

A water pipe tapers down from an initial radius of R1 = 0.21 m to a final radius of R2 = 0.11 m. The water flows at a velocity v

Aleks [24]

Answer:

$0.116 m^3/s$

Explanation:

The volume flow rate of a fluid in a pipe is given by:

$Q=Av$

where

A is the cross-sectional area of the pipe

v is the speed of the fluid

In this problem, at the initial point we have

v = 0.84 m/s is the speed of the water

r = 0.21 m is the radius of the pipe, so the cross-sectional area is

$A=\pi r^2 = \pi (0.21 m)^2 =0.138 m^2$

So, the volume flow rate is

$Q=(0.138 m^2)(0.84 m/s)=0.116 m^3/s$

8 0

3 years ago

Take a look at the pic and please help me

Hoochie [10]

Sodium Hydroxide is highly Basic

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3 years ago