Answer:
The water potential of a solution of 0.15 M sucrose solution is -3.406 bar.
Explanation:
Water potential = Pressure potential + solute potential
We have :
C = 0.15 M, T = 273.15 K
i = 1
The water potential of a solution of 0.15 m sucrose= 
(At standard temperature)
The water potential of a solution of 0.15 M sucrose solution is -3.406 bar.
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The answer of this question is B. Tessa could use more plants and multiple trials
Explanation: In Tessa’s experiment, she has two sea grape plants and gives one pure water and the other a strong salt water solution. Tessa is trying to determine which amount of salt is the BEST for sea grape. With the experiment she set up however, she isn’t going to be able to determine which amount of salt is the BEST for the sea grape because she is only giving one sea grape plant salt. If Tessa were to have more sea grape plants and gave them all different amounts of salt, she could determine which amount of salt is best for the sea grape.
Hope this helped! If you have any questions about my answer feel free to comment on the question.
Answer:
At STP one mole of any gas occupies a volume of 22.4 L: this is the molar volume.
Explanation:
