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nasty-shy [4]
3 years ago
15

I need help pls.. and thank you..

Mathematics
1 answer:
zmey [24]3 years ago
4 0
40 times 24 times 154 divided by 2 will give you the answer.
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Write a division problem that has a two digit quotient that is greater than 40 but less than 50.
trasher [3.6K]

Let

x--------> Dividend

y-------> Divisor

Q-------> Quotient

we know that

\frac{x}{y} = Q

solve for x

x=Q*y

40 < Q < 50

Examples

example 1

Q=45\\ y=4

Find the value of x

x=45*4\\ x=180

A division problem is equal to

\frac{x}{y} =\frac{180}{4} \\\\ = 45

example 2

Q=42\\ y=10

Find the value of x

x=42*10\\ x=420

A division problem is equal to

\frac{x}{y} =\frac{420}{10} \\\\ = 42

8 0
3 years ago
Read 2 more answers
What is the value of x?
zaharov [31]

Answer: around 47-49

Step-by-step explanation:

5 0
3 years ago
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The first three steps for solving the quadratic equation by completing the square are shown. Fill in the missing number in the l
gulaghasi [49]
Completing the square is done as follows:

1. Write the equation in a way that the constants are in the right side while the terms with x are on the left. 
<span>9x2 +54x = 7
</span>
2. Make sure that the coefficient of the x^2 term is 1.
<span>9(x2 + 6x) = 7
</span>
3. Adding a term to both sides that will complete the square in the left side. This is done by dividing the coefficient of the x term by 2 and squaring it. Note: The same amount should be added to the right side to balance the equation.
<span>9(x2 + 6x + 9) = 7 + 81

9(x+3)^2 = 88
</span>
5 0
3 years ago
Read 2 more answers
Please answer 3x^2 - 18x - 48 = 0
Dafna1 [17]

Answer:

Solution

x=8

x=−2

Step-by-step explanation:

iiiiii

5 0
2 years ago
Read 2 more answers
JKLM is a rhombus. KM is 20 and JL is 48. Find the perimeter of the<br><br> rhombus.
anygoal [31]

Answer:

104 units

Step-by-step explanation:

Given

Shape: Rhombus

JL = 48

KM = 20

Required

Determine the perimeter

The given parameter are the diagonals of the rhombus.

The perimeter (from diagonals) is calculated as thus:

P = 2\sqrt{(JL)^2 + (KM)^2}

Substitute values for JL and KM

P = 2\sqrt{48^2 + 20^2}

P = 2\sqrt{2304 +400}

P = 2\sqrt{2704}

P = 2 * 52

P = 104

<em>Hence, the perimeter is 104 units</em>

5 0
3 years ago
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