What is the number of orbitals in an atom of radon

For each of the following choose the variable that will be more favorable in solution formation. A) Weak or Strong Solvent inter

Deffense [45]

Based on factors affecting solution formation;

Strong solvent-solute intermolecular forces favors solution formation.
Increase in entropy favours solution formation
Decrease in enthalpy favours solution formation

<h3>What is a solution?</h3>

A solution is a substance formed when a substance known as solute dissolves in another substance know as solvent.

Factors that affect solution formation include:

strength of intermolecular forces between solute and solvent
entropy
enthalpy

Strong solvent-solute intermolecular forces favors solution formation.

Increase in entropy favours solution formation

Decrease in enthalpy favours solution formation.

Learn more about solutions at: brainly.com/question/6675586

6 0

2 years ago

Hey everyone!! Can someone please explain the periodic table of elements and whoever wants to talk I can talk to!!

Burka [1]

Answer:

The periodic table of elements arranges all of the known chemical elements in an informative array. Elements are arranged from left to right and top to bottom in order of increasing atomic number. Order generally coincides with increasing atomic mass. ... For instance, all the group 18 elements are inert gases.

Explanation:

3 0

3 years ago

If 16.00 g of O₂ reacts with 80.00 g NO, how many the excess reactant are left over? (enter only the value, round to whole numbe

pishuonlain [190]

Answer:

50

Explanation:

We will need a balanced equation with masses, moles, and molar masses of the compounds involved.

1. Gather all the information in one place with molar masses above the formulas and masses below them.

Mᵣ: 30.01 32.00 46.01

2NO + O₂ ⟶ 2NO₂

Mass/g: 80.00 16.00

2. Calculate the moles of each reactant

$\text{moles of NO} = \text{80.00 g NO} \times \dfrac{\text{1 mol NO}}{\text{30.01 g NO}} = \text{2.666 mol NO}\\\\\text{moles of O}_{2} = \text{16.00 g O}_{2} \times \dfrac{\text{1 mol O}_{2}}{\text{32.00 g O}_{2}} = \text{0.5000 mol O}_{2}$

3. Calculate the moles of NO₂ we can obtain from each reactant

From NO:

The molar ratio is 2 mol NO₂:2 mol NO

$\text{Moles of NO}_{2} = \text{2.333 mol NO} \times \dfrac{\text{2 mol NO}_{2}}{\text{2 mol NO}} = \text{2.333 mol NO}_{2}$

From O₂:

The molar ratio is 2 mol NO₂:1 mol O₂

$\text{Moles of NO}_{2} = \text{0.5000 mol O}_{2}\times \dfrac{\text{2 mol NO}_{2}}{\text{1 mol Cl}_{2}} = \text{1.000 mol NO}_{2}$

4. Identify the limiting and excess reactants

The limiting reactant is O₂ because it gives the smaller amount of NO₂.

The excess reactant is NO.

5. Mass of excess reactant

(a) Moles of NO reacted

The molar ratio is 2 mol NO:1 mol O₂

$\text{Moles reacted} = \text{0.500 mol O}_{2} \times \dfrac{\text{2 mol NO}}{\text{1 mol O}_{2}} = \text{1.000 mol NO}$

(b) Mass of NO reacted

$\text{Mass reacted} = \text{1.000 mol NO} \times \dfrac{\text{30.01 g NO}}{\text{1 mol NO}} = \text{30.01 g NO}$

(c) Mass of NO remaining

Mass remaining = original mass – mass reacted = (80.00 - 30.01) g = 50 g NO

5 0

3 years ago

Balance the following chemical reactions:

Tcecarenko [31]

1. 2Pb(NO₃)₂ → 2PbO + 4NO₂ + O₂

2. CH₄ + 2O₂ → CO₂ + 2H₂O

3. Cu + 2AgNO₃ → Cu(NO₃)₂ + 2Ag

4. MnO₂ + 4HCl → MnCl₂ + 2H₂O + Cl₂

5. Pb(NO₃)₂ + 2NaCl → PbCl₂ + 2NaNO₃

1)

$NaCl+AgNO_3=>NaNO_3+AgC\downarrow$

2)

CuSO_4+Cu_2Cl_2\neq>

$CuSO_4+Cu_2l_2\neq$

4 0

3 years ago

Read 2 more answers

What process is used to refine aluminum from its ore bauxite?

Murljashka [212]

Answer:

D. Smelting

Explanation:

Bauxite is the aluminum ore from which alumina, also known as aluminum oxide, Al₂O₃, is produced. Bauxite is extracted from the topsoil regions of some subtropical and tropical regions, and the Bayer process is primarily then used to produce alumina from the bauxite.

Aluminum is produced from the alumina by an aluminum smelting process known as the Hall—Heroult electrolytic process which involves the use of a carbon anode and direct current to produce aluminum by reducing the aluminum oxide

7 0

3 years ago