Types of Bonds can be predicted by calculating the
difference in electronegativity.
If, Electronegativity difference is,
Less
than 0.4 then it is Non Polar Pure Covalent
Between 0.4 and 1.7 then it is Polar Covalent
Greater than 1.7 then it is Ionic
For Br and Br,
E.N of Bromine = 2.96
E.N of Bromine = 2.96
________
E.N Difference
0.00 (Non Polar/Pure Covalent)
For N and O,
E.N of Oxygen = 3.44
E.N of Nitrogen = 3.04
________
E.N Difference
0.40 (Non Polar/Pure Covalent)
For P and H,
E.N of Hydrogen = 2.20
E.N of Phosphorous = 2.19
________
E.N Difference 0.01 (Non Polar/Pure Covalent)
For K and O,
E.N of Oxygen = 3.44
E.N of Potassium = 0.82
________
E.N Difference 2.62 (Ionic)
Answer:
they leads to water full of village
Explanation:
the trend in electropositivity in group 1
Li < Na < K < Rb < Cs
Answer:
2 and 3
Explanation:
An element belongs to group 4 and period 3.
Over here you have to use the formula: <span>P1/T1= P2/T2
P1= 7.58
T1= 639
P2= ?
T2= 311
</span><span>7.58/639 = ?/311
</span>= 3.689 kPa
