From the calculations, the pH of the buffer is 3.1.
<h3>What is the pH of the buffer solution?</h3>
The Henderson-Hasselbach equation comes in handy when we deal with the pH of a buffer solution. From that equation;
pH = pKa + log[(salt/acid]
Amount of the salt = 25/1000 * 0.50 M = 0.0125 moles
Amount of the acid = 75/1000 * 1.00 M = 0.075 moles
Total volume = ( 25 + 75)/1000 = 0.1 L
Molarity of salt = 0.0125 moles/0.1 L = 0.125 M
Molarity of the acid = 0.075 moles/0.1 L = 0.75 M
Given that the pKa of lactic acid is 3.86
pH = 3.86 + log( 0.125/0.75)
pH = 3.1
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Answer:
That is extremely confusing. Try contacting your prof.
Explanation:
Answer: I believe that it's electrons please let me know if it was right or what it was!
Hope this helps!!! Good luck!!! ;)
Answer:
It is the last one.
Explanation:
Water molecules are polar, they have cohesive properties, and water is less dense when it is solid than when it is a liquid, that is why ice floats in liquid water. However, water is a very good solvent, it can dissolve many solids, including sugar, salt, and other hydrophilic substances.
