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inysia [295]
3 years ago
12

Atoms in a stays in a fixed position I have no freedom to move

Physics
1 answer:
Triss [41]3 years ago
8 0
Is a solid...
when atoms or molecules or particles are in a fixed position it is a solid, it only vibrates in its place.
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A policeman investigating an accident measures the skid marks left by a car on the horizontal road. He determines that the dista
sleet_krkn [62]
<h2>The velocity of car was m m/s </h2>

Explanation:

When the car skids , its centripetal force is provided by frictional force .

Here centripetal force F = \frac{mv^2}{r}

here v is the velocity of car and r is the radius of the curve .

The frictional force f = μ R

here μ is the coefficient of kinetic friction and R is normal reaction

Thus f =  m g

On horizontal road R = mg

Thus F = f  at the time of skid .

Thus v = \sqrt{\mu rg}

= \sqrt{0.29x23.74x10} = 9 m/s

3 0
3 years ago
Which word contains a prefix that means against?
Firlakuza [10]
B - antidepressant (anti meaning against)
4 0
4 years ago
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Four point charges are individually brought from infinity and placed at the corners of a square. Each charge has the identical v
Brut [27]

To solve this problem we will apply the concept of voltage given by Coulomb's laws. From there we will define the charges and the distance, and we will obtain the total value of the potential difference in the system.

The length of diagonal is given as

l = 2a

The distance of the center of the square from each of the corners is

r = \frac{2a}{2}= a

The potential electric at the center due to each cornet charge is

V_1 = \frac{kQ_1}{r_1}

V_2 = \frac{kQ_2}{r_2}

V_3 = \frac{kQ_3}{r_3}

V_4 = \frac{kQ_4}{r_4}

The total electric potential at the center of the given square is

V = V_1+V_2+V_3+V_4

V = \frac{kQ_1}{r_1}+ \frac{kQ_2}{r_2}+\frac{kQ_3}{r_3}+\frac{kQ_4}{r_4}

Al the charges are equal, and the distance are equal to a, then

V = \frac{kQ}{a}+ \frac{kQ}{a}+\frac{kQ}{a}+\frac{kQ}{a}

V = \frac{4kQ}{a}

Therefore the correct option is E.

3 0
4 years ago
The pressure in an automobile tire is 198 kpa at 300.0 k. at the end of a trip on a hot, sunny day, the pressure has risen to 22
Kamila [148]

We can use the ideal gas equation which is expressed as PV = nRT. At a constant volume and number of moles of the gas the ratio of T and P is equal to some constant. At another set of condition, the constant is still the same. Calculations are as follows:

T1/P1 = T2/P2

T2 = P2 x T1 / P1

T2 = 225 x 300 / 198

<span>T2 = 340.91 K</span>

3 0
4 years ago
Friction, conduction and induction are three ways of creating a static charge on an object. Which method or methods will produce
blondinia [14]

The method that would produce the same charge is conduction only.

7 0
4 years ago
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