Answer:
the normal force that the wall exerts on the ball
Explanation:
As Newton's third law states:
"when an object A exerts a force on object B, then object B exerts an equal and opposite force on object A".
If we apply this law to this problem, we can identify the ball as object A, and the wall as object B. As the ball hits the wall, the ball exerts a force on the wall (toward the direction of motion of the ball), so the wall exerts an equal and opposite force on the ball (in the opposite direction). This force is the normal force of the wall, and it is responsible for pushing the ball back towards Erica.
Which picture are you talking about?
Total mechanical energy = kinetic energy + potential energy
E = KE + PE
E = ½mv² + mgh
E = ½(0.1 kg)(2 m/s)² + (0.1 kg)(9.8 m/s²)(1.5 m)
E = 0.2 J + 1.47 J
E = 1.67 J
The strength of electric field E is 17 N / C.
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<u>Explanation:</u>
Electric field strength is defined as the force per unit charge acting at a point in the given field. The equation for the strength of the electric field is given by
E = F / q
where E represents the electric field strength,
F represents the force in newton,
q represents the charge in coulomb.
Given the charge q = 0.30 coulombs
force F = 5.0 N
Electric field strength E = force / charge
= 5.0 / 0.30
E = 16.66 = 17 N / C.
