The law is Newton's first law or called the law of inertia; Which just means that an object at rest stays at rest and an object in motion stays in motion and continues at the same speed and in the same direction unless acted upon by an outside force force.
Answer:True
Explanation:
A ideal solution is a solution which obeys Raoults law on almost every concentration and temperature range.
Ideal solutions are formed by mixing those solute and solvent which has identical molecular properties.
Lets take A be the solute and B be the solvent so to form a ideal solution from these components the solute-solute(A-A) molecular interaction and solvent -solvent (B-B) molecular interactions must be identical with the solute solvent interaction(A-B).
The solute-solute molecular interaction ,solute-solvent molecular interaction and solvent-solvent molecular interaction must be equal in order to form a ideal solution.
The enthalpy of mixing and volume of mixing of ideal solution is zero.
enthalpy of mixing is the amount of energy released on mixing a solute and solvent and in case of ideal solutions it is zero.
Volume of mixing is change in volume on mixing a solute and solvent.
<h2>a)
The rate at which
is formed is 0.066 M/s</h2><h2>b)
The rate at which molecular oxygen
is reacting is 0.033 M/s</h2>
Explanation:
Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.
Rate in terms of disappearance of
=
= 0.066 M/s
Rate in terms of disappearance of
= ![-\frac{1d[O_2]}{dt}](https://tex.z-dn.net/?f=-%5Cfrac%7B1d%5BO_2%5D%7D%7Bdt%7D)
Rate in terms of appearance of
= ![\frac{1d[NO_2]}{2dt}](https://tex.z-dn.net/?f=%5Cfrac%7B1d%5BNO_2%5D%7D%7B2dt%7D)
1. The rate of formation of 
![-\frac{d[NO_2]}{2dt}=\frac{1d[NO]}{2dt}](https://tex.z-dn.net/?f=-%5Cfrac%7Bd%5BNO_2%5D%7D%7B2dt%7D%3D%5Cfrac%7B1d%5BNO%5D%7D%7B2dt%7D)
![\frac{1d[NO_2]}{dt}=\frac{2}{2}\times 0.066M/s=0.066M/s](https://tex.z-dn.net/?f=%5Cfrac%7B1d%5BNO_2%5D%7D%7Bdt%7D%3D%5Cfrac%7B2%7D%7B2%7D%5Ctimes%200.066M%2Fs%3D0.066M%2Fs)
2. The rate of disappearance of 
![-\frac{1d[O_2]}{dt}=\frac{d[NO]}{2dt}](https://tex.z-dn.net/?f=-%5Cfrac%7B1d%5BO_2%5D%7D%7Bdt%7D%3D%5Cfrac%7Bd%5BNO%5D%7D%7B2dt%7D)
![-\frac{1d[O_2]}{dt}=\frac{1}{2}\times 0.066M/s=0.033M/s](https://tex.z-dn.net/?f=-%5Cfrac%7B1d%5BO_2%5D%7D%7Bdt%7D%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%200.066M%2Fs%3D0.033M%2Fs)
Learn more about rate law
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https://brainly.in/question/1297322
Answer:
True;
True;
False;
True;
True.
Explanation:
Organic compounds can be found pure, but generally, they are in mixtures, such as the petroleum, so it is possible to the compound received be impure;
Organic compounds can be found in the three states: solid, liquid or gas. The state will depend on the molecular forces in it and its molar mass. For example, gasoline is liquid in the ambient temperature, natural gas is a gas, and the glucose is solid;
The main characteristic of the organic compounds is the presence of C and H, the other elements can or can't be in the structure: O, N, halogens, and S;
Because of the carbon can form chains, there are several million possible known organic compounds;
The spectroscopic would give some results such as composition, molar mass, and diffraction, and with these results, it would be possible to identify some chemical properties and the tests needs more identification.
Answer:
Option A.
Explanation:
1 mol of anything contains 6.02×10²³ particles.
We know that 1 mol of oxygen gas contains 2 moles of O.
1 mol of oxygen weighs 16 g/mol, the mass for 1 molecule of O.
By the way, the mass for 1 mol of O₂ may be:
Option A → 16 g/mol . 2 mol
32 g
Oyxgen is a dyatomic molecule, that's why we have 2 moles of O.
Another example can be:
1 mol of water (H₂O) contains 2 moles of H and 1 mol of O.