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goldenfox [79]
3 years ago
7

Calculate the mass of sucrose needed to prepare a 2000 grams of 2.5% sucrose solution.

Chemistry
1 answer:
OlgaM077 [116]3 years ago
4 0

Explanation:

= 2.5\% \times 2000 \\  =  \frac{2.5}{100}  \times 2000 \\  = 50 \: g

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Study the reaction. X(s) + 2B(aq)→ X+(aq) + B2(g) Under which circumstances will the reaction rate be highest? A) the solid X is
Tems11 [23]

Answer:

Option (A) the solid X is ground to a fine powder.

Explanation:

X(s) + 2B(aq) → X+(aq) + B2(g)

In the reaction above, the rate of the reaction will be highest, when X being a solid is ground to fine powder.

Grounding X to fine powder simply means increasing the surface area of X.

An increase in surface area of reactants will definitely increase the rate of reaction because the particles of the solid will collide with the right orientation and hence speed up the reaction rate.

6 0
3 years ago
A chemist prepares a solution of silver(I) nitrate by measuring out of silver(I) nitrate into a volumetric flask and filling the
leva [86]

Answer:

3.33 M

Explanation:

It seems your question is incomplete, however, that same fragment has been found somewhere else in the web:

" <em>A chemist prepares a solution of silver nitrate (AgNO3) by measuring out 85.g of silver nitrate into a 150.mL volumetric flask and filling the flask to the mark with water.</em>

<em>Calculate the concentration in mol/L of the chemist's silver nitrate solution. Be sure your answer has the correct number of significant digits.</em> "

In this case, first we <u>calculate the moles of AgNO₃</u>, using its molecular weight:

  • 85.0 g AgNO₃ ÷ 169.87 g/mol = 0.500 mol AgNO₃

Then we<u> convert the 150 mL of the volumetric flask into L</u>:

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Finally we <u>divide the moles by the volume</u>:

  • 0.500 mol AgNO₃ / 0.150 L = 3.33 M
4 0
3 years ago
15.0 g of Fe and 25.0 g of sand are added to 250.0 g of water. a. Determine the percent mass of Fe, sand, and water in the mixtu
lana [24]

Answer:

A. percentage mass of iron = 5.17%

percentage mass of sand  = 8.62%

percentage mass of water = 86.205%

B. (Iron + sand + water) -------> ( iron + sand) ------> sand

C. The step of separation of iron and sand

Explanation:

A. Percentage mass of the mixtures:

Total mass of mixture = (15.0 + 25.0 + 250.0) g =290.0 g

percentage mass of iron = 15/290 * 100% = 5.17%

percentage mass of sand = 25/290 * 100% = 8.62%

percentage mass of water = 250/290 * 100% = 86.205%

B. Flow chart of separation procedure

(Iron + sand + water) -------> separation by filtration using filter paper and funnel to remove water --------> ( iron + sand) -----------> separation using magnet to remove iron ------> sand

C. The step of separation of iron and sand by magnetization of iron will have the highest amount of error because during the process, some iron particles may not readily be attracted to the magnet as they may have become interlaced in-between sand grains. Also, some sand particle may also be attracted to the magnet as they are are borne on iron particles.

5 0
3 years ago
Making models involves creating representations of complex objects or processes to help people study and understand things that
swat32
Somewhat false
observations can be made of a model of the statue of liberty, say, or in real line
6 0
3 years ago
What volume of 0.350 m koh is required to react completely with 24.0 ml of 0.650 m h3po4?
BartSMP [9]

The complete balanced chemical equation for this is:

<span>3KOH  +  H3PO4  -->  K3PO4  +  3H2O</span>

 

First we calculate the number of moles of H3PO4:

moles H3PO4 = 0.650 moles / L * 0.024 L = 0.0156 mol

 

From stoichiometry, 3 moles of KOH is required for every mole of H3PO4, therefore:

moles KOH = 0.0156 mol H3PO4 * (3 moles KOH / 1 mole H3PO4) = 0.0468 mol

 

Calculating for volume given molarity of 0.350 M KOH:

Volume = 0.0468 mol / (0.350 mol / L) = 0.1337 L = 133.7 mL

 

Answer:

<span>133.7 mL KOH</span>

7 0
3 years ago
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