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amid [387]
2 years ago
6

What is the density of a 700 kg object with a volume of 649 m3? (Density: D = ) 0.927 kg/m3 .4543 kg/m3 1.079 kg/m3 4.543 kg/m3

Chemistry
2 answers:
alexandr1967 [171]2 years ago
7 0

The density  of 700 kg object  with  a volume of 649 m³  is 1.079  kg/M³


 calculation

  This problem is solved using density  = mass /volume   formula

mass= 700 kg

volume= 649 m³


density is therefore =  700 kg / 649 m³  = 1.079 kg/m³

alekssr [168]2 years ago
3 0
The answer to your question is the third option "1.079 kg/m<span>3
</span>"
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Answer : The vapor pressure of hexane = 140.5055 torr

Solution :  Given,

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From the Raoult's law, the vapor pressure of the component is equal to the vapor pressure of the pure component multiplied by its mole fraction.

Formula used :

P_{i}=P_{i}^{*}\times x_{i}      ..............(1)

Where,

P_{i} = vapor pressure of component i

P_{i}^{*} = vapor pressure of pure component i

x_{i} = mole fraction of of component i in the solution

For this problem, few steps are involved:

step 1 : concentration of 10% naphthalene by mass means 10 g of naphthalene present in 100 g of solution.

This means,

The mass of naphthalene = 10 g

The mass of hexane = 100 - 10 = 90 g

step 2 : find the number of moles of naphthalene and hexane.

Formula used :  

Number of moles = \frac{\text{ Given mass}}{\text{ Molar mass}}

Moles of Naphthalene = \frac{10g}{128g/mole} = 0.0781 moles

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Total moles = Moles of Naphthalene + Moles of Hexane

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step 3 : Now, calculate mole fraction of Hexane

Mole fraction of Hexane = \frac{\text{ Moles of Hexane}}{\text{ Total moles}} = \frac{1.0465}{1.1246} = 0.9305

step 4 : Now, find the vapor pressure of Hexane by using above formula (1).

P_{i}=P_{i}^{*}\times x_{i}  

Now put all the values in this formula, we get

Vapor pressure of Hexane = Vapor pressure of pure Hexane × Mole fraction of Hexane

P_{i} = 151 torr × 0.9305 = 140.5055 torr

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