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Mnenie [13.5K]
3 years ago
12

How many deciliter a of a .88M Lif solution be made using 25.5 cg Lif? Lif molar mass = 25.94 g/mol

Chemistry
1 answer:
sasho [114]3 years ago
8 0
<h3>Answer:</h3>

0.112 deciliter

<h3>Explanation:</h3>
  • Molarity of a solution shows the amount of solute in moles contained in a liter of solution.
  • Therefore; Molarity = Number of moles ÷ Volume of solvent in liters

In this case we are given;

Molarity of LiF as 0.88 M

Mass of LiF as 25.5 cg

but, 1 g = 100 cg

Therefore, mass of LiF = 0.255 g

Molar mass of LiF = 25.94 g/mol

We are required to calculate the volume of LiF in deciliter

<h3>Step 1: Determine the number of moles of LiF</h3>

Moles = Mass ÷ Molar mass

          = 0.255 g ÷ 25.94 g/mol

          = 0.00983 mole

<h3>Step 2: Determine the volume of LiF</h3>

Molarity = Moles ÷ Volume

Rearranging the formula;

Volume = Moles ÷ Molarity

Volume of LiF = 0.00983 mole ÷ 0.88 moles/liter

                        = 0.0112 L

But, 1 L = 10 DL

Therefore, Volume = 0.112 DL

Thus, the volume of LiF is 0.112 deciliter

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29.0g silver combine completely with 4.30g of sulfur to form a compound. what is the percent composition of this compound?
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Answer:

Percentage of silver and sulphur in the compound  is 87.08% and 12.91%  respectively

Explanation:

Given:

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\text { percent of compound }=\frac{\text { amount of element }}{\text { Total Molecule Mass }} \times 100

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\text { Percentage of silver }=\frac{\text { amount of silver }}{\text { Total Molecule Mass }} \times 100

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\text { Percentage of silver }=\frac{\text {amount of suplhur}}{\text { Total Molecule Mass }} \times 100

=>\frac{4.30}{33.3}\times 100

=>0.1291\times 100

=> 12.91%

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