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Archy [21]
3 years ago
10

Does the average speed go up, down or stay the same?

Physics
1 answer:
Crank3 years ago
6 0
Stays the same I’m guessing
You might be interested in
Please help! Calculate velocity. Show all work!
Eduardwww [97]

Answer:

v = 23.66 m/s

Explanation:

recall that one of the equations of motion may be expressed:

v² = u² + 2as,

Where

v = final velocity (we are asked to find this)

u = initial velocity = 0 m/s since we are told that it starts from rest

a = acceleration = 0.56m/s²

s = distance traveled = given as 500m

Simply substitute the known values into the equation:

v² = u² + 2as

v² = 0 + 2(0.56)(500)

v² = 560

v = √560

v = 23.66 m/s

4 0
3 years ago
James rode his bike 0.65 hours and traveled 8.45 km. What was his speed?
maria [59]

Speed = (distance covered) / (time to cover the distance)

            =    ( 8.45 km)   /   (0.65 hr)

            =         (8.45 / 0.65)  km/hr

            =                  13 km/hr
5 0
3 years ago
Sapting Leng You have a string with a mass of 13.7 q. You stretch the string with a force of 8.39 N, giving it a length of 1.87
marshall27 [118]

Answer:

a)  \lambda=0.935\ \textup{m}

b) f=36.19\approx 36\ \textup{Hz}

Explanation:

Given:

String vibrates transversely fourth dynamic, thus n = 4

mass of the string, m = 13.7 g = 13.7 × 10⁻¹³ kg

Tension in the string, T = 8.39 N

Length of the string, L = 1.87 m

a) we know

L= n\frac{\lambda}{2}

where,

\lambda = wavelength

on substituting the values, we get

1.87= 4\times \frac{\lambda}{2}

or

\lambda=0.935\ \textup{m}

b) Speed of the wave (v) in the string is given as:

v =f\lambda

also,

v=\sqrt\frac{T}{(\frac{m}{L})}

equating both the formula for 'v' we get,

f\lambda=\sqrt\frac{T}{(\frac{m}{L})}

on substituting the values, we get

f\times 0.935=\sqrt\frac{8.39}{(\frac{13.7\times 10^{3}}{1.87})}

or

f=\frac{33.84}{0.935}

or

f=36.19\approx 36\ \textup{Hz}

5 0
3 years ago
Explain why it is better to jump and land with bent knees rather than straight legs? Use key physics vocabulary.
BigorU [14]

Answer:

Bent knees

Explanation:

Depending the height your jumping from, if you were jumping from a high structure it's best if you jump and land on knees so you dont sprang your ankles from jumping and landing on your straight legs, you could even pull a muscle if you land on straight legs.

3 0
3 years ago
what are 3 CHEMICAL REACTIONS that you personally observed over the last 2 weeks. You should only include chemical reactions tha
Allisa [31]

1).  I started up my car.  Gasoline was spritzed into the cylinders, mixed with air, and then exploded with an electrical spark.  As the gasoline vapor instantly burned in the air, several new things were formed that weren't there before, like carbon dioxide, carbon monoxide, water, and oxides of nitrogen.

2).  I left my dinner on the stove a little too long, and it got a layer of crunchy crackly sooty carbon on the bottom. That part of it didn't taste too good.  This isn't exactly something that happens every day, but more often than I'd like it too.

3).  All day, every day, and all night, every night, about 10 or 20 times every minute, I pull air into my lungs.  I keep it there for a while, then I blow it out and pull in some fresh stuff.  The air I blow out has less oxygen and more carbon dioxide in it than it had when I pulled it in.  That's because of the hundreds of chemical reactions going on inside my body, to keep me alive and functioning.  I hope these keep going on for many many more days in the future.  

6 0
3 years ago
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