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AVprozaik [17]
3 years ago
14

what can you infer about copper and sliver based on their position relative to each other on the periodic table?

Physics
2 answers:
victus00 [196]3 years ago
8 0
Both are metals, conduct electricity, and likely have similar amounts of certain atoms that only metals, electricity conveying materials, and a few others have.
timofeeve [1]3 years ago
4 0
Both are metals and are good conductors of electricity and heat.
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A 20 g ball is fired horizontally with speed v0 toward a 100 g ball hanging motionless from a 1.0-m-long string. The balls un-de
sladkih [1.3K]

Answer:7.93 m/s

Explanation:

Given

mass of ball m_1=20\ gm

Mass of hanging ball m_2=100\ gm

Length of string L=1\ m

Maximum angle turned \theta _{max}=50^{\circ}

v_o is the initial velocity of ball 1  and 0 is the initial  velocity of ball 2

For Perfectly elastic final velocity of ball 1 and 2 is given by

v_2'=\frac{2m_1}{m_1+m_2}\cdot v_1-\frac{m_1-m_2}{m_1+m_2}\cdot v_2

v_1'=\frac{m_1-m_2}{m_1+m_2}\cdot v_1+\frac{2m_2}{m_1+m_2}\cdot v_2

where v_1and v_2 are the velocity of 1 and 2 before collision

thus v_2'=\frac{2\times 20}{120}v_0-0

v_2'=\frac{v_o}{3}

v_1'=\frac{20-100}{120}\times v_o+0

v_1'=-\frac{2}{3}v_o

By energy conservation on second ball we get

Kinetic energy=Potential Energy

\frac{1}{2}m_2(v_2')^2=m_2gL(1-\cos \theta )

v_2'=\sqrt{2gl(1-\cos \theta )}

v_2'=\sqrt{2\times 9.8\times 1(1-0.642)}

v_2'=2.64\ m/s

thus v_o=3\times v_2'=7.93\ m/s

5 0
4 years ago
Help me. It's question 2 I need the answer for
Alex73 [517]
Ok, let me see if I can help

Sound is caused by vibrations. These can pass through a solid, liquid, and gas. But not through vacuum because there are no particles
6 0
3 years ago
The potential energy of an apple is 19.6 J, and it is 8 m above the ground. The mass of the apple is _____ kg
Crazy boy [7]
We know, U = mgh
Substitute the known values, 
19.6 = m * 9.8 * 8
m = 19.6 / 78.4
m = 1/4

In short, Your Answer would be 1/4 Kg

Hope this helps!
8 0
3 years ago
A pickup truck has a width of 79.0 in. If it is traveling north at 42 m/s through a magnetic field with vertical component of
bekas [8.4K]

Answer:

The magnitude of the induced Emf is 0.003371V

Explanation:

The width of the truck is given as 79inch but we need to convert to meter for consistency, then

The width= 79inch × 0.0254=2.0066 metres.

Now we can calculate the induced Emf using expresion below;

Then the induced EMF= B L v

Where B= magnetic field component

L= width

V= velocity

=(40*10^-6) × (42) × (2.0066)

=0.003371V

Therefore, the magnitude emf that is induced between the driver and passenger sides of the truck is 0.003371V

8 0
4 years ago
Two small spheres spaced 20.0 cm apart have equal charge. How many excess electrons must be present on each sphere if the magnit
Snowcat [4.5K]

Answer:

894 electrons

Explanation:

The electrostatic force between the two charges is given by:

F=\frac{k q_1 q_2}{r^2}

where we have

F=4.57\cdot 10^{-21} N is the force

k is the Coulomb's constant

q1 = q2 =q is the magnitude of the charge on each sphere

r = 20.0 cm = 0.20 m is the distance between the two spheres

Substituting and solving for q, we find the charge on each sphere:

q=\sqrt{\frac{Fr^2}{k}}=\sqrt{\frac{(4.57\cdot 10^{-21} N)(0.20 m)^2}{9\cdot 10^9 Nm^2C^{-2}}}=1.43\cdot 10^{-16} C

And since each electron has a charge of

e=1.6\cdot 10^{-19}C

the net charge on each sphere will be given by

q=Ne

where N is the number of excess electrons; solving for N,

N=\frac{q}{e}=\frac{1.43\cdot 10^{-16}C}{1.6\cdot 10^{-19}C}=894

7 0
4 years ago
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