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3 years ago

what can you infer about copper and sliver based on their position relative to each other on the periodic table?

2 answers:

8 0

Both are metals, conduct electricity, and likely have similar amounts of certain atoms that only metals, electricity conveying materials, and a few others have.

timofeeve [1]3 years ago

4 0

Both are metals and are good conductors of electricity and heat.

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A 20 g ball is fired horizontally with speed v0 toward a 100 g ball hanging motionless from a 1.0-m-long string. The balls un-de

sladkih [1.3K]

Answer:7.93 m/s

Explanation:

Given

mass of ball $m_1=20\ gm$

Mass of hanging ball $m_2=100\ gm$

Length of string $L=1\ m$

Maximum angle turned $\theta _{max}=50^{\circ}$

$v_o$ is the initial velocity of ball 1 and 0 is the initial velocity of ball 2

For Perfectly elastic final velocity of ball 1 and 2 is given by

$v_2'=\frac{2m_1}{m_1+m_2}\cdot v_1-\frac{m_1-m_2}{m_1+m_2}\cdot v_2$

$v_1'=\frac{m_1-m_2}{m_1+m_2}\cdot v_1+\frac{2m_2}{m_1+m_2}\cdot v_2$

where $v_1$ and $v_2$ are the velocity of 1 and 2 before collision

thus $v_2'=\frac{2\times 20}{120}v_0-0$

$v_2'=\frac{v_o}{3}$

$v_1'=\frac{20-100}{120}\times v_o+0$

$v_1'=-\frac{2}{3}v_o$

By energy conservation on second ball we get

Kinetic energy=Potential Energy

$\frac{1}{2}m_2(v_2')^2=m_2gL(1-\cos \theta )$

$v_2'=\sqrt{2gl(1-\cos \theta )}$

$v_2'=\sqrt{2\times 9.8\times 1(1-0.642)}$

$v_2'=2.64\ m/s$

thus $v_o=3\times v_2'=7.93\ m/s$

5 0

4 years ago

Help me. It's question 2 I need the answer for

Alex73 [517]

Ok, let me see if I can help

Sound is caused by vibrations. These can pass through a solid, liquid, and gas. But not through vacuum because there are no particles

6 0

3 years ago

The potential energy of an apple is 19.6 J, and it is 8 m above the ground. The mass of the apple is _____ kg

Crazy boy [7]

We know, U = mgh
Substitute the known values,
19.6 = m * 9.8 * 8
m = 19.6 / 78.4
m = 1/4

In short, Your Answer would be 1/4 Kg

Hope this helps!

8 0

3 years ago

A pickup truck has a width of 79.0 in. If it is traveling north at 42 m/s through a magnetic field with vertical component of

bekas [8.4K]

Answer:

The magnitude of the induced Emf is $0.003371V$