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Roman55 [17]
3 years ago
10

The horse on a carousel is 3.5m from the central axis.A. If the carousel rotates at 0.13 rev/s , how long does it take the horse

to go around twice?B. How fast is a child on the horse going (in m/s)?
Physics
1 answer:
Kitty [74]3 years ago
8 0

Answer:

a. 15.4 seconds

b. 0.455 m/s

Explanation:

a. The carousel rotates at 0.13 rev/s.

This means that it takes the carousel 1 sec to make 0.13 of an entire revolution.

This means that time it will take to make a complete revolution is:

1 / 0.13 = 7.7 seconds

Therefore, the time it will take to make 2 revolutions is:

2 * 7.7 = 15.4 seconds

b. Let us calculate the linear velocity. Angular velocity is given as:

\omega = v / r

where v = linear velocity and r = radius

The radius of the circle is 3.5 m and the angular velocity is 0.13 rev/s, therefore:

0.13 = v / 3.5

v = 3.5 * 0.13 = 0.455 m/s

Linear velocity is 0.455 m/s

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Given that force is applied at an angle of 30 degree below the horizontal

So let say force applied if F

now its two components are given as

F_x = Fcos30


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Now the normal force on the block is given as

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N = 0.5F + (18\times 9.8)

N = 0.5F + 176.4

now the friction force on the cart is given as

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F_f = 110.25 + 0.3125F

now if cart moves with constant speed then net force on cart must be zero

so now we have

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3 years ago
When 525 J of heat is added to 7.6 g of metal at 26°C, the temperature increases to 80°C. What is the specific heat of the metal
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if a material has a half-life of 24 hours, how long do you have to wait until the amount of radioisotope is 1/4 its original amo
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Answer:

48 hours

Explanation:

Using the formula,

R/R' = 2ᵃ/ᵇ..................... Equation 1

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Substitute into equation 1

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