The object would have a centripetal acceleration <em>a</em> of
<em>a</em> = (12 m/s)² / (0.7 m) ≈ 205.714 m/s²
so that the required tension in the string would be
<em>T</em> = (0.5 kg) <em>a</em> ≈ 102.857 N ≈ 100 N
(rounding to 1 significant digit)
Answer:
A
Explanation:
i can't see the picture, it is blocked off, can you write down your question?
Two point charges are separated by 6.4 cm . The attractive force between them is 10 N .
units.
a the atom loses 1 proton to have a total of 34
