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Answer:
The car stops after 32.58 m.
Explanation:
t = Time taken for the car to stop
u = Initial velocity = 20 m/s
v = Final velocity = 0
s = Displacement
a = Acceleration = -6 m/s²
Time taken by the car to stop

Total Time taken by the car to stop is 0.5+3.33 = 3.83 s

The car stops after 32.58 m.
Distance between car and obstacle is 50-32.58 = 17.42 m
<h2>Answer: Any new and abnormal growth</h2>
A <u>neoplasm</u> is any <u>uncontrolled growth</u> of abnormal cells or tissues in the body.
This abnormal mass can be benign or malignant (carcinogenic).
Therefore, the correct option is D.
You can solve this using the equation k=mv^2. k is the kinetic energy, m is the mass, and is the velocity. k=30(3.4)^2, so the answer is 346.8 J.
The distance for any rectilinear motion at constant acceleration is:
d = v₀t + 0.5at²
where
v₀ is the initial velocity
So, if v₀ = 6v, and it stopped to 0 m/s, then the acceleration is equal to:
a = (0 - 6v)/t = -6v/t
Thus,
d = (6v)(t) + (0.5)(-6v/t)(t²)
d = 6vt - 3t
<span>d = 3t(2v - 1)</span>