Answer:
Explanation:
Amplitude is 35/2=17.5
Midline= Distance from ground + Amplitude = 17.5+3= 20.5
Period is time taken to finish 6 minutes
2π/b=T
2π/b=6
b=π/3
An unstretched spring has a length of 0.30 m. When the spring is stretched to a total length of 0.60 m, it supports traveling wa
ves moving at 4.5 m/s. How fast will waves travel on this spring if it is stretched to 0.90 m?
1 answer:
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Answer:
spring deflection is x = (v2 / R + g) m / 4
Explanation:
We will solve this problem with Newton's second law. Let's analyze the situation the car goes down a road and finds a dip (hollow) that we will assume that it has a circular shape in the lower part has the car weight, elastic force and a centripetal acceleration
Let's write the equations on the Y axis of this description
Fe - W = m
Where Fe is elastic force, W the weight and the centripetal acceleration. The elastic force equation is
Fe = - k x
4 (k x) - mg = m v² / R
The four is because there are four springs, R is theradio of dip
We can calculate the deflection (x) of the springs
x = (m v2 / R + mg) / 4
x = (v2 / R + g) m / 4
- Force=700N
- Acceleration=9.8m/s^2
Using newtons law