All categories

4 years ago

Is this correct? plssssssssss help me

Chemistry

2 answers:

MAXImum [283]4 years ago

5 0

You are correct.

Grass grows rapidly, and sometimes you can't even tell. That's what he means

Keep being brainy! :)

Irina-Kira [14]4 years ago

3 0

This is not correct.

You might be interested in

For the equilibrium

Mamont248 [21]

Answer:

Equilibrium concentrations of the gases are

$H_2S=0.596M$

$H_2=0.004 M$

$S_2=0.002 M$

Explanation:

We are given that for the equilibrium

$2H_2S\rightleftharpoons 2H_2(g)+S_2(g)$

$k_c=9.0\times 10^{-8}$

Temperature, $T=700^{\circ}C$

Initial concentration of

$H_2S=0.30M$

$H_2=0.30 M$

$S_2=0.150 M$

We have to find the equilibrium concentration of gases.

After certain time

2x number of moles of reactant reduced and form product

Concentration of

$H_2S=0.30+2x$

$H_2=0.30-2x$

$S_2=0.150-x$

At equilibrium

Equilibrium constant

$K_c=\frac{product}{Reactant}=\frac{[H_2]^2[S_2]}{[H_2S]^2}$

Substitute the values

$9\times 10^{-8}=\frac{(0.30-2x)^2(0.150-x)}{(0.30+2x)^2}$

By solving we get

$x\approx 0.148$

Now, equilibrium concentration of gases

$H_2S=0.30+2(0.148)=0.596M$

$H_2=0.30-2(0.148)=0.004 M$

$S_2=0.150-0.148=0.002 M$

3 0

3 years ago

The definition for adrenaline

hram777 [196]

A hormone secreted by the adrenal glands, especially in conditions of stress, increasing rates of blood circulation, breathing, and carbohydrate metabolism and preparing muscles for exertion.

6 0

3 years ago

Read 2 more answers

An experimental series stack of PEM cells produces 2.20 x 108 W of power. If each cell contributes 231 kW, how many cells are in

Phoenix [80]

The Answer is 952 cells!

I hope this helps! ^^

4 0

4 years ago

Read 2 more answers

The enthalpy of combustion of octane is -5470 kJ/mol. Octane (formulae C8H18) was used to heat some water in a copper can. The a

Virty [35]

Answer: 0.0009 moles of octane were used up.

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$

Given mass of octane = 0.1 g

Molar mass of octane = 11.23 g/mol

Putting in the values we get:

$\text{Moles of octane}=\frac{0.1g}{114.23g/mol}=0.0009moles$

Thus 0.0009 moles of octane were used up.

7 0

4 years ago

What is the concentration, in mol/L of an HCl solution if 22.86 mL reacts completely with (neutralizes) 29.64 mL of a 0.1037 M s

insens350 [35]

Ask if something is not clear

6 0

3 years ago