Answer:
e. Both the acceleration and net force on the car point inward.
Explanation:
If no net force acts on the car, the car must drive in a straight line, at constant speed.
As the acceleration is defined as the rate of change of the velocity vector, this means that it can produce either a change in the magnitude of the velocity (the speed) or in the direction.
In order to the car can follow a circular trajectory, it must be subjected to an acceleration, that must go inward, trying to take the car towards the center of the circle.
The net force that causes this acceleration, aims inward, and is called the centripetal force.
It is not a different type of force, it can be a friction force, a tension force, a normal force, etc., as needed.
Answer: λ2= 2.34 * 10^-6 C/m
Explanation: In order to calculate the value of the linear charge density of the insulating shell we have to multiply ρ* Volume of the hollow cylinder, so
Volume of cylinder:2*π*b*L *(b-a) where (b-a) is the thickness, then
λ2=Q/L = 634 *10^-6 C/m^3* 2*π*0.042 m*(0.042-0.26)== 2.34 μ C/m
A-11 polar easterlies
b-8 winds blowing between the equator and 30° N and south
c-10
d-9
Answer:
69.69 g
Explanation:
Evaporation of water will take out latent heat of vaporization. Let the mass of water be m and latent heat of vaporization of water be 2260000 J per kg
Heat taken up by evaporating water
= 2260000 x m J
Heat lost by body
= mass x specific heat of body x drop in temperature
60 x 3500 x .750 ( specific heat of human body is 3.5 kJ/kg.k)
= 157500 J
Heat loss = heat gain
2260000 m= 157500
m = .06969 kg
= 69.69 g
Answer:
a
The mass is 
b
The velocity is 
Explanation:
From the question we are told that
The speed of the protons is 
The mass of the protons is 
The speed of the rebounding protons are 
The negative sign shows that it is moving in the opposite direction
Now according to the law of energy conservation mass of one nucleus of the unknown element. is mathematically represented as
![m_2 = [\frac{u_1 -v_1}{u_1 + v_1} ] m_1](https://tex.z-dn.net/?f=m_2%20%3D%20%5B%5Cfrac%7Bu_1%20-v_1%7D%7Bu_1%20%2B%20v_1%7D%20%5D%20m_1)
Where 
is the mass of a single proton
So substituting values
The mass of on proton is 
So 
Now according to the law of linear momentum conservation the speed of the unknown nucleus immediately after such a collision is mathematically evaluated as
Now 
because before collision the the nucleus was at rest
So
=> 
Recall that
So
=> 
substituting values
