Answer:
50 m/s opposite direction to the motion of the truck
Explanation:
From the question,
Applying the law of conservation of momentum
mu+m'u' = V(m+m')...….. Equation 1
Where m = mass of the truck, u = initial velocity of the truck, m' = mass of the car, u' = initial velocity of the car, V = Final velocity after collision
Given: m = 2500 kg, u = 20 m/s, m' = 1000 kg, V = 0 m/s (both car stop after collision)
Substitute these values into equation 1
2500(20)+1000(u') = 0(2500+1000)
2500(20)+1000(u') = 0
Solve for u'
u' = -[2500(20)]/1000
u' = -50 m/s
The negative sign shows that the car travels in opposite direction to the truck
Hence the car initial velocity before collision is 50 m/s in opposite direction to the motion of the truck
No force is required to lift that balloon. In fact, force is required to hold it down, and if you let go, it's up, up, and away.
Since the balloon's density is less than the density of the air around it, it's lighter than the air it displaces, there is a net upward buoyant force acting on it, and it floats up !
Answer:
Without this slack, a locomotive might simply sit still and spin its wheels. The loose coupling enables a longer time for the entire train to gain momentum, requiring less force of the locomotive wheels against the track. In this way, the overall required impulse is broken into a series of smaller impulses. (This loose coupling can be very important for braking as well).
Explanation:
<span>A free body diagram is a representation of how the forces that are acting on a point or particle interact. You place your point at the origin and then draw your forces.
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