Consider the medium of air as defined by the use of radio frequency. What made some of the early standards so slow compared to t
1 answer:
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Answer:
The magnitude of the static frictional force is 1200 N
Explanation:
given information :
radius, r = 0.380 m
applied-torque, τ1 = 456 N
The car has a constant velocity, thus the acceleration is zero
α = 0
Στ = I α
τ1 - τ2 = I α
τ2 = counter-torque
τ1 - τ2 = 0
τ1 = τ2
r x = τ1
= the static frictional force (N)
= τ1 /r
= 456 N/0.380 m
= 1200 N
Answer:
(e) 3.2
Explanation:
We are given that vector C and D.
Let R be the magnitude of C+D.
According to question
R=3D
We have to find the ratio of the magnitude of C to that of D.
By using right triangle property
Hence, the ratio of the magnitude of C to that of D=3.2
(e) 3.2
Answer:
Both will reach to same height
Explanation:
Here we can see that friction is to be ignored
so we can say that work done by all the non conservative forces is change in mechanical energy
Since all non conservative forces here is zero
so mechanical energy is conserved here
so here we can say that sum of initial kinetic energy and potential energy = sum of final kinetic energy and potential energy
So we will have
now maximum height is given as
so here we can say that greatest height will be independent of the mass so they both will reach at same height