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defon
3 years ago
15

Consider the medium of air as defined by the use of radio frequency. What made some of the early standards so slow compared to t

oday's 802.11n 300Mbps and higher bandwidth
Physics
1 answer:
Tanzania [10]3 years ago
3 0

Answer:

Explanation:

Earliest standards were dependent on a single frequency/channel to both send and receive. This shared medium creates the same problem as half-duplex coax cable. Because receivers had to wait for the signal before sending a response, this reduced the overall bandwidth.

Other factors affect wireless signal propagation, too, including RF interference, antenna choice, and obstacles such as walls, trees, and even weather (precipitation, for example).

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Acceleration = (final velocity^2 - initial velocity^2) / 2 * distance

Acceleration = (19.1^2 - 9.2^2) / 2 * 32

Acceleration = (364.81 - 84.64) / 64

Acceleration = 280.17 / 64

Acceleration = 4.3777m/s^2

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Organism undergo constant chemical changes as they maintain an internal balance known as?
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Suppose an automobile has 2000-joules of kinetic energy. when it moves at twice the speed, what will be its kinetic energy? what
NeX [460]

Answer:

K.Eₓ = 4 K.E

K.Eₓ = 9 K.E

Explanation:

Th formula for the kinetic energy of a body is given as follows:

K.E = \frac{1}{2}mv^2\\   ---------------equation (1)

where,

K.E = Kinetic Energy of Automobile

m = mass of automobile

v = speed of automobile

For twice speed:

vₓ = 2v

then,

K.E_{x} = \frac{1}{2}mv_{x}^2\\K.E_{x} = \frac{1}{2}m(2v)^2\\K.E_{x} = 4\frac{1}{2}mv^2\\

using equation (1):

<u>K.Eₓ = 4 K.E</u>

For thrice speed:

vₓ = 3v

then,

K.E_{x} = \frac{1}{2}mv_{x}^2\\K.E_{x} = \frac{1}{2}m(3v)^2\\K.E_{x} = 9\frac{1}{2}mv^2\\

using equation (1):

<u>K.Eₓ = 9 K.E</u>

6 0
3 years ago
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