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tatyana61 [14]
4 years ago
11

An unknown element, x, reacts with lithium to form the compound li2x. in other compounds this element also can accommodate up to

12 electrons rather than the usual octet. what element could x be?
Chemistry
2 answers:
Anika [276]4 years ago
8 0

Answer:

X could be S, Se, Te, Po or Lv.

Explanation:

From the formula Li_{2} X, it can be determined the charge of the ion X:

Li is a metal from the group 1 (alkaline metal) in the periodic table,so the only charge possible for it is +1.  As the formula contains two Li, the total positive charge gives +2. This impplies that X must holds a charge of -2.

Inspection of the periodic table shows that atoms that commonly gain two electrons forming -2 charged anions are the ones in group 16.

The second part of the text  states that X can accommodate 12 electrons expanding its octect. This effect can be observed in atoms that have empty d-orbitals available to accomodate those extra electrons. Thus, atoms from period 3 and above show octect expansion.

The elements that are in group 16 in period 3 or above are S, Se, Te, Po and Lv.

aliina [53]4 years ago
7 0
<span>Answer Choices: 
A) Ca 
B) O 
C) Cl 
D) s</span>

<span>the formula is Li2X, so the charge on the X anion must be 2- 

the ion is X2- elements in group 6A form monatomic ions with a 2- charge. In your list that is O or Po 

If the element can accomodate 12 electrons then it can have an expanded octet. Only elements in period 3 and higher can have expanded octets. 

So you are looking for a group 6A element in period 3 or higher.
cA would not intereact with LI BECAUSE ITS A METAL The only element that fits the bill is D) S</span>

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Oksi-84 [34.3K]

Answer:

oil and vinegar

the rest would mix well so you can't determine the individual components

Explanation:

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3 years ago
Which element has similar properties to Berylium? Explain
GaryK [48]
This has multiple answers can you be more specific
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For the net reaction: 2AB + 2C → A2 + 2BC, the following slow first steps have been proposed. AB → A + B 2C + AB → AC + BC 2AB →
puteri [66]

This is an incomplete question, here is a complete question.

For the net reaction: 2AB + 2C → A2 + 2BC, the following slow first steps have been proposed.

(1) AB → A + B

(2) 2C + AB → AC + BC

(3) 2AB → A₂ + 2B

(4) C + AB → BC + A

What rate law is predicted by each of these steps?

Answer : The rate law expression for the following reactions are:

(1) \text{Rate}=k[AB]

(2) \text{Rate}=k[C]^2[AB]

(3) \text{Rate}=k[AB]^2

(4) \text{Rate}=k[C][AB]

Explanation :

Rate law : It is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

The general reaction is:

A+B\rightarrow C+D

The general rate law expression for the reaction is:

\text{Rate}=k[A]^a[B]^b

where,

a = order with respect to A

b = order with respect to B

R = rate  law

k = rate constant

[A] and [B] = concentration of A and B reactant

Now we have to determine the rate law for the given reaction.

(1) The balanced equations will be:

AB\rightarrow A+B

In this reaction, AB is the reactant.

The rate law expression for the reaction is:

\text{Rate}=k[AB]

(2) The balanced equations will be:

2C+AB\rightarrow AC+BC

In this reaction, C and AB are the reactants.

The rate law expression for the reaction is:

\text{Rate}=k[C]^2[AB]

(3) The balanced equations will be:

2AB\rightarrow A_2+2B

In this reaction, AB is the reactant.

The rate law expression for the reaction is:

\text{Rate}=k[AB]^2

(4) The balanced equations will be:

C+AB\rightarrow BC+A

In this reaction, C and AB are the reactants.

The rate law expression for the reaction is:

\text{Rate}=k[C][AB]

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serg [7]
2KCIO3=2KCL+302
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8 0
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svp [43]
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here h2 H2 is limiting reagent
6moles of H2 will give 4moles of NH3
V of NH3 produced=22.4*4L
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