How many moles of potassium chlorate are needed to produce 5.25 moles of oxygen
1 answer:
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<u>Answer:</u> The mass of HCl present in 500 mL of acid solution is 36.5 grams
<u>Explanation:</u>
To calculate the concentration of acid, we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of acid which is HCl
are the n-factor, molarity and volume of base which is NaOH.
We are given:
Putting values in above equation, we get:
To calculate the mass of solute, we use the equation used to calculate the molarity of solution:
Molar mass of HCl = 36.5 g/mol
Molarity of solution = 2 M
Volume of solution = 500 mL
Putting values in above equation, we get:
Hence, the mass of HCl present in 500 mL of acid solution is 36.5 grams