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melamori03 [73]
3 years ago
11

Which of these is NOT a factor considered is describing the climate of a region?

Chemistry
1 answer:
Lostsunrise [7]3 years ago
3 0

Answer:

the population of the region

Hope this helps :)

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Describe in your own words, why a balloon, after it has been rubbed on a sweater, floats back towards the sweater when released.
MrRissso [65]

Explanation:

By rubbing the balloon on a sweater, you can transfer negative charges onto the surface of the balloon

8 0
3 years ago
a galvanic cell zn | zn²⁺ || ni²⁺ | ni runs spontaneously. if a current is imposed to turn this into an electrolytic cell, which
hodyreva [135]

Answer:

Zn²⁺ gets reduced

Explanation:

An electrolytic cell runs in the opposite direction of a galvanic cell. Applying a current to the galvanic cell Zn | Zn²⁺ || Ni²⁺ | Ni would convert the Zn anode to a cathode and cause Zn²⁺ to be reduced.

8 0
3 years ago
A chemist prepares a solution of silver(II) oxide by measuring out 0.0013 of silver(II) oxide into a 100 mL volumetric flask and
azamat

Answer:

1.3x10⁻⁸ mol/L

Explanation:

<em>0.0013μmol, Calculate concentration in mol/L</em>

<em />

To obtain concentration in mol/L we need to convert the μmoles to moles and mL to liters:

<em>Moles silver(II) oxide:</em>

0.0013μmol × (1mol / 1x10⁶μmol) = 1.3x10⁻⁹ moles

<em>Liters solution:</em>

100mL * (1L / 1000mL) = 0.1L

That means concentration in mol/L is:

1.3x10⁻⁹ moles / 0.1L =

<h3>1.3x10⁻⁸ mol/L</h3>
6 0
3 years ago
What is the approximate value of the equilibrium constant, k n, for the neutralization of acetic acid withsodium hydroxide, show
NikAS [45]
You are given the neutralization of acetic acid with sodium hydroxide. Also, you are given the k for acetic acid, which is 1.8 x 10⁻⁵. You are asked to find the<span> approximate value of the equilibrium constant, kn, for the neutralization. We will have a reaction of both acetic acid and sodium hydroxide.

CH</span>₃COOH + NaOH → CH₃COONa + H₂O
which comes from
CH₃COOH → CH₃COO⁻ + H⁺
H⁺ + OH⁻ → H₂O<span>

</span>The k for water is always 1.0 x 10¹⁴. The Ksp for the reaction will be
<span>
Ksp = [</span>CH₃COOH][H₂O]
Ksp = (1.8 x 10⁻⁵)(1.0 x 10¹⁴)
<span>Ksp = 1.8 x 10</span>⁹
5 0
3 years ago
If you had 240 L container at 479 k and 300 kpa, what would the volume be if you changed the conditions to STP
nydimaria [60]

Answer:

The answer to your question is V2 = 434.7 l

Explanation:

Data

Volume 1 = V1 = 240 l                             Volume 2 = ?

Temperature 1 = T1 = 479°K                   Temperature 2 = T2 = 293°K

Pressure 1 = P1 = 300 KPa                      Pressure 2 = P2 = 101.325 Kpa

Process

1.- Use the combined gas law to solve this problem

                P1V1/T1 = P2V2/t2

-Solve for V2

               V2 = P1V1T2 / T1P2

2.- Substitution

                V2 = (300)(240)(293) / (479)(101.325)

3.- Simplification

                V2 = 21096000 / 48534.675

4.- Result

                V2 = 434.7 l

6 0
3 years ago
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