Is the component perpendicular to the surface on contact of the contact force <span />
Answer:
Speed; v = 17 m/s
Explanation:
We are given;
Radius; r = 110m
Angle; θ = 15°
Now, we know that in circular motion,
v² = rg•tanθ
Thus,
v = √(rg•tanθ)
Where,
v is velocity
r is radius
g is acceleration due to gravity
θ is the angle
Thus,
v = √(rg•tanθ) = √(110 x 9.8•tan15)
v = √(288.85)
v = 17 m/s
E=mcθ
where E is the energy added,m is the mass,c is the specfic heat capacity and θ is the change in temprature.
making m subject u get E/c<span>θ=m
</span><span>θ=(30-20)=10</span><span>
plugging the values we get :
</span>

<span>
solving it we get the answer that is 0.25kg or 250 grams
</span>
Answer:
a = -04978 m / s²
Explanation:
For this exercise we can use the kinematics equations, as the initial speed, distance and time indicate, we can use
x = x₀ + v₀ t + 1 /2 a t²
½ a t² = x-x₀ - v₀ t
a = (x-x₀ - v₀ t) 2 / t²
let's reduce the magnitudes to the SI system
x₀ = 1000 mm = 1 m
x = 5000mm = 5m
let's calculate
a = (5 - 1 - 15 60) 2/60²
a = -04978 m / s²
negative sign indicates that braking is related