Answer: a. air pollution
c. hazardous wastes
d. potential reactor accident
e. water pollution
A nuclear energy is produced in a thermal power plant. A nuclear energy is produced in a nuclear reactor. In nuclear reactor nuclear fission reactions takes place in which an atoms absorbs energy from radiations and undergo fission and produces energy in the form of high intensity radiations along with heat. Although the fission reactions takes place in a nuclear reactor in a controlled way so that the radiation may not leak out from the reactor. The accidentally leak out radiations or explosion or bursting of the reactor due to uncontrolled thermal energy production can result in air pollution as the leak out air will cause bursting effects which will contaminate the air.
The nuclear waste are radioactive and are non-biodegradable these wastes are disposed off deep in geospheres and in water. They have potential to contaminate both land and water. Radioactive wastes can cause mutations in the genome of the organisms exposed to these wastes which generate deadly diseases and disorders. Therefore, these wastes are hazardous.
To solve this problem we need the concepts of Energy fluency and Intensity from chemical elements.
The energy fluency is given by the equation
![\Psi=4RcE\pi](https://tex.z-dn.net/?f=%5CPsi%3D4RcE%5Cpi)
Where
The energy fluency
c = Activity of the source
r = distance
E = electric field
In the other hand we have the equation for current in materials, which is given by
![I= I_0 e^{-\mu_{h20}X_{h2o}} e^{-\mu_{Fe}X_{Fe}}](https://tex.z-dn.net/?f=I%3D%20I_0%20e%5E%7B-%5Cmu_%7Bh20%7DX_%7Bh2o%7D%7D%20e%5E%7B-%5Cmu_%7BFe%7DX_%7BFe%7D%7D)
Then replacing our values we have that
![I = 1*10^{-3} * 3.3*10^{10} * e ^{-0.06*1.1} e^{-0.058*7.861}](https://tex.z-dn.net/?f=I%20%3D%201%2A10%5E%7B-3%7D%20%2A%203.3%2A10%5E%7B10%7D%20%2A%20e%20%5E%7B-0.06%2A1.1%7D%20e%5E%7B-0.058%2A7.861%7D)
![I = 1.3*10^7 Bq](https://tex.z-dn.net/?f=I%20%3D%201.3%2A10%5E7%20Bq)
We can conclude in this part that 1.3*10^7Bq is the activity coming out of the cylinder.
Now the energy fluency would be,
![\Psi = \frac{cE}{4\pir^2}](https://tex.z-dn.net/?f=%5CPsi%20%3D%20%5Cfrac%7BcE%7D%7B4%5Cpir%5E2%7D)
![\Psi = \frac{1.3*10^7*2*1.25}{4\pi*11^2}](https://tex.z-dn.net/?f=%5CPsi%20%3D%20%5Cfrac%7B1.3%2A10%5E7%2A2%2A1.25%7D%7B4%5Cpi%2A11%5E2%7D)
![\Psi = 2.14*10^4 MeV/cm^2.s](https://tex.z-dn.net/?f=%5CPsi%20%3D%202.14%2A10%5E4%20MeV%2Fcm%5E2.s)
The uncollided flux density at the outer surface of the tank nearest the source is ![\Psi = 2.14*10^4 MeV/cm^2.s](https://tex.z-dn.net/?f=%5CPsi%20%3D%202.14%2A10%5E4%20MeV%2Fcm%5E2.s)
Then everyone would fall off the surface
Answer:
To calculate the predicted surface elevation of a 50km thick crust above a surface of 2.5km we are given a density of 3 gram per centimeter cube.
The displacement of the material will be calculated by subtracting the surface elevation of 2.5 km from the 50 km thick crust. Therefore 50-25= 47.5 km.
Thus let the density of the material be Pm
50*3= 47.5*Pm
Therefore: Pm= (50*3)/47.5= 3.16gram per centimeter cube
Thus with an average density of 2.8gram per centimeter cube
50*2.8= (50-x)*3.16
(50-x)= (50*2.8)/3.16
50-x=44.3
x=50-44.3= 5.7
Explanation:
To calculate the predicted surface elevation of a 50km thick crust above a surface of 2.5km we are given a density of 3 gram per centimeter cube.
The displacement of the material will be calculated by subtracting the surface elevation of 2.5 km from the 50 km thick crust. Therefore 50-25= 47.5 km.
Thus let the density of the material be Pm
50*3= 47.5*Pm
Therefore: Pm= (50*3)/47.5= 3.16gram per centimeter cube
Thus with an average density of 2.8gram per centimeter cube
50*2.8= (50-x)*3.16
(50-x)= (50*2.8)/3.16
50-x=44.3
x=50-44.3= 5.7
Answer:
Block A will have a final charge of 3.5nC.
Explanation:
This is because at the point of contact with Block B, which is electrically positive, the electrons in Block A will be attracted to the excess 'unpaired' protons in block B. Hence, the electrons will flow into Block B causing unpaired protons to remain in Block A.
This process is called Charging by Conduction.
This charging process will continue until the charges are evenly distributed between both objects.
In case you're wondering, "<em>how's all this possible within a few seconds</em>?", remember that electrons travel very fast and so, this process is a rather rapid one.