Based in the information given, the data that'll be affected by the error is the value of the solvent data.
It should be noted that the data that'll be affected based on the scenario given is the value of the solvent. When the preparation is kept overnight, there'll be an overflow of the solvent.
In such a case, it'll be difficult to get the correct distance that the solvent travelled. The effect on the calculated Rr is that the <em>calculated Rr</em> will be incorrect due to the error in solvent value.
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All of the following cause mechanical weathering EXCEPT d. carbonic acid, which causes chemical weathering. Mechanical weathering is defined as a physical process where rocks are broken down into smaller pieces through movement, abrasion, pressure, and temperature changes. Chemical weathering, on the other hand, makes use of chemical reactions to break down rocks.
J.J. Thomson hypothesized and discovered that the atom was not the smallest unit of matter but that instead there were much smaller units. He discovered "sub-atomic particles" which make up atoms. The sub-atomic particle that Thomson discovered was the electron. He discovered this through a process of experiments testing cathode rays.
4.2 grams i think i hope this helps
Answer:
The empirical formula is: CH2
Th powder is not vainillin
Explanation:
We can find empirical formula of a compound CₐHₓOₙ knowing that moles CO2 = Moles C, 2 Moles H2O = Moles H and that we can find the mass of oxygen by the difference of masses of the atoms:
<em>Moles C = Moles CO2 -Molar mass: 44.01g/mol-</em>
5.875g * (1mol/44.01g) = 0.1335 moles C * (12.01g/mol) = 1.60gC
<em>Moles H2O and moles H -Molar mass: 18.01g/mol-</em>
2.41g H2O * (1mol / 18.01g) = 0.1339 moles H2O * (2mol H / 1mol H2O) =
0.2676 moles H * (1g/mol) = 0.27g H
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The empirical formula of this compound is the ratio of C:H:
0.2676 moles H / 0.1335 moles C = 2
The empirical formula is:
CH2
In vainillin, the moles of Carbon = Moles of Hydrogen. the experiment shows the moles of hydrogen are twice the moles of carbon. Thus, the powder is not vainillin