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Viefleur [7K]
3 years ago
6

I need help. ASAP! Look at the picture below. (4)

Chemistry
2 answers:
Bezzdna [24]3 years ago
7 0

The answer would be B, double covalent bond... I would think.

jekas [21]3 years ago
3 0

I believe the answer is B.

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Convert 30 g of Na O to liters.​
Bess [88]

Answer:

0.03 liters

Explanation:

1g = 0.001L

30 * 0.001 = 0.03L

Best of Luck!

5 0
3 years ago
Read 2 more answers
What is the order in which electrons start filling the orbitals?
emmainna [20.7K]

a. 1s 2s 2p 3s 3p 4s 3d 4p is the correct option.

This gives the following order to fill the orbit: 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d, 7p, (8s, 5g, 6f, 7d, 8p, and 9s)

Aufbau's principle states that electrons fill low-energy atomic orbitals before they fill high-energy atomic orbitals. .. By following this rule, you can predict the electron configuration of an atom or ion.

There may be two electrons at the maximum of one orbit. Since the s subplane has only one orbit, it can hold up to two electrons. The p subplane has three orbitals, so it can hold up to six electrons. The d-subplane has five orbitals, so it can hold up to 10 electrons.

Learn more about electrons here:brainly.com/question/11316046

#SPJ4

4 0
2 years ago
Name this alkane.
svetlana [45]

Answer:

no te entiendo pasa

Explanation:

no te entiendo pasa

7 0
2 years ago
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How many oxygen molecules are required for glycolysis
morpeh [17]

Answer:

0

Explanation:

glycolysis requires no oxygen

6 0
2 years ago
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Complete combustion of a 17.12mg sample of xylene In oxygen yielded 56.77mg
Veronika [31]

Xylene moles =\frac{17.12}{106.16×1000}=0.00016moles=

106.16×1000

17.12

=0.00016moles

Moles of CO_2 =\frac{56.77}{44.01×1000}=0.0013CO

2

=

44.01×1000

56.77

=0.0013

Moles of H_2O= =\frac{14.53}{18.02×1000}=0.0008H

2

O==

18.02×1000

14.53

=0.0008

Moles ratios

\frac{0.0013}{0.0008}=1.625

0.0008

0.0013

=1.625

\frac{0.0008}{0.0008}=1

0.0008

0.0008

=1

Hence molecular fomula

The empirical formula is C 4H 5.

The molecular formula C8H10

8 0
2 years ago
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