How many moles are in 25.0 grams of KMnO4?
1 answer:
Answer:- 0.158 moles
Solution:- Moles are calculated on dividing the grams by the molar mass.
25.0 grams of are given and we are asked to calculate the moles.
For this we need the molar mass so let's calculate it first.
Molar mass is the sum of atomic masses of all the atoms present in the molecule.
Molar mass =
= 158.036 gram per mol
Now, we will divide the given grams by molar mass to get the moles and the set is shown as:
=
So, there are 0.158 moles of .
You might be interested in
Answer:
All of the above.
Explanation:
In positive deviation from Raoult's Law occur when the vapour pressure of components is greater than what is expected value in Raoult's law.
When a solution is non ideal then it shows positive or negative deviation.
Let two solutions A and B to form non- ideal solutions.let the vapour pressure of component A is and vapour pressure of component B is
.
= Vapour pressure of component A in pure form
= Vapour pressure of component B in pure form
=Mole fraction of component A
=Mole fraction of component B
The interaction between A- B is less than the interaction A- A and B-B interaction.Therefore, the escaping tendency of liquid molecules in mixture is greater than the escaping tendency in pure form.Hence, the vapour pressure of a mixture is greater than the initial value of vapour pressure.
,
Therefore,
Therefore, the enthalpy of mixing is greater than zero and change in volume is greater than zero.
Hence, option a,b,c and d are true.