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Lunna [17]
3 years ago
6

How many moles are in 25.0 grams of KMnO4?

Chemistry
1 answer:
Lilit [14]3 years ago
3 0

Answer:- 0.158 moles

Solution:- Moles are calculated on dividing the grams by the molar mass.

25.0 grams of KMnO_4 are given and we are asked to calculate the moles.

For this we need the molar mass so let's calculate it first.

Molar mass is the sum of atomic masses of all the atoms present in the molecule.

Molar mass = 39.098+54.938+4(16)

= 158.036 gram per mol

Now, we will divide the given grams by molar mass to get the moles and the set is shown as:

25.0gKMnO_4(\frac{1mol}{158.036g})

= 0.158molKMnO_4

So, there are 0.158 moles of KMnO_4 .

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Calculate the number of moles in 7g of nitrogen gas​
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Answer:

<h3>0.2498molN_{2}</h3>

Explanation:

7gN2 x \frac{1 mol}{2(14.01) g}

=0.2498mol N2

Nitrogen gas has the formula N_{2} so therefore that means you would have to multiply the mass in the molar by 2. To solve for the number of moles you need to cancel out the grams, you do this by using the molar mass of nitrgoen gas. You get the value on in the denominator from the periodic table (atomic mass of element). The grams will cancel out, leaving you with the number of moles when you divide 7/2(14.01).

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3 years ago
What is the heat of vaporization of water?
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The molecules in liquid water are held together by relatively strong hydrogen bonds and its enthalpy of vaporization, 40.65 kJ/mol is more than five times the energy required to heat the same quantity of water from: 0 °C to 100 °C (cp = 75.3 J K−1 mol−1).

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7 0
3 years ago
What is wrong with or ambiguous about the phrase "four molecules of NaCl"?
Alex787 [66]

Answer:

the NaCl is not considered a molecula

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Molecules are atoms bound with chemical bond.

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7 0
3 years ago
Read 2 more answers
Nail polish remover containing acetone was spilled in a room 7.2 m × 5.8 m × 3.9 m. Measurements indicated that 6,400 mg of acet
sergeinik [125]

Volume of room  = 7.2 m \times 5.8 m \times  3.9 m

= 162.864 m^{3}

Now, according to conversion factor, convert 6,400 mg to micrograms

Since, 1 mg is equal to 1000 microgram.

Therefore, 6,400 mg  = 6,400 \times 1000

= 6,400,000 micrograms of acetone.

To calculate concentration of acetone, divide volume and evaporated amount of acetone in micrograms.

Thus,

Concentration of acetone  = \frac{6,400,000 microgram}{162.864 m^{3}}

= 39296.5910 microgram per cubic meter or 3.92\times 10^{4} \mu g/m^{3}\simeq 4.0\times 10^{4} \mu g/m^{3}

Hence, concentration of acetone is equal to 4.0\times 10^{4} \mu g/m^{3}

7 0
3 years ago
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