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KIM [24]
3 years ago
15

When the material left behind has been carried by the glacier from its original location to a new location, this is called what

Physics
2 answers:
MAVERICK [17]3 years ago
3 0

Answer:

C

Explanation:

Glaciers break rocks because of the thawing and icing of water in rock crevices. These rocks get carried in the glacier. The glaciers move because the base of the glaciers melts ever so slightly due to the weight of the glacier above (pressure reduces the melting point of ice). This smoothens the slipping of the glaciers . When the glaciers get to a warmer place, it melts and the rocks in it are deposited.

VashaNatasha [74]3 years ago
3 0

Answer:

C)Glacial deposition

Explanation:

Glacial deposition involves the carrying of earth materials by moving glaciers and releasing them in another place.

The movement of the materials from one place to another involves the action of the glacier. When the glacier thaws or begins to melt, the materials carried in the freeze becomes deposited and released. Glaciers are powerful agent of denudation as they can carry earth materials of different sizes from one place and deposit them in another place entirely.

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To solve this problem we will apply the concepts related to energy conservation. From this conservation we will find the magnitude of the amplitude. Later for the second part, we will need to find the period, from which it will be possible to obtain the speed of the body.

A) Conservation of Energy,

KE = PE

\frac{1}{2} mv ^2 = \frac{1}{2} k A^2

Here,

m = Mass

v = Velocity

k = Spring constant

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Rearranging to find the Amplitude we have,

A = \sqrt{\frac{mv^2}{k}}

Replacing,

A = \sqrt{\frac{(0.750)(31*10^{-2})^2}{13}}

A = 0.0744m

(B) For this part we will begin by applying the concept of Period, this in order to find the speed defined in the mass-spring systems.

The Period is defined as

T = 2\pi \sqrt{\frac{m}{k}}

Replacing,

T = 2\pi \sqrt{\frac{0.750}{13}}

T= 1.509s

Now the velocity is described as,

v = \frac{2\pi}{T} * \sqrt{A^2-x^2}

v = \frac{2\pi}{T} * \sqrt{A^2-0.75A^2}

We have all the values, then replacing,

v = \frac{2\pi}{1.509}\sqrt{(0.0744)^2-(0.750(0.0744))^2}

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2 years ago
compare to visible light, the wavelength of x-rays is shorter longer or the same and the frequency is lower higher or the same
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Answer:shorter higher

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Explanation:

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URGENT!!! sorry this is my first time using brainly! but here is my question: Two ropes are attached to a wagon, one horizontal
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The components of the net force on the cart is determined as 67.66 N.

<h3>Component of net force on the cart</h3>

The component of net force on the cart is determined by resolving the forces into x and y -components.

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T2 = 40 N

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