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KIM [24]
3 years ago
15

When the material left behind has been carried by the glacier from its original location to a new location, this is called what

Physics
2 answers:
MAVERICK [17]3 years ago
3 0

Answer:

C

Explanation:

Glaciers break rocks because of the thawing and icing of water in rock crevices. These rocks get carried in the glacier. The glaciers move because the base of the glaciers melts ever so slightly due to the weight of the glacier above (pressure reduces the melting point of ice). This smoothens the slipping of the glaciers . When the glaciers get to a warmer place, it melts and the rocks in it are deposited.

VashaNatasha [74]3 years ago
3 0

Answer:

C)Glacial deposition

Explanation:

Glacial deposition involves the carrying of earth materials by moving glaciers and releasing them in another place.

The movement of the materials from one place to another involves the action of the glacier. When the glacier thaws or begins to melt, the materials carried in the freeze becomes deposited and released. Glaciers are powerful agent of denudation as they can carry earth materials of different sizes from one place and deposit them in another place entirely.

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A marble at the front of a truck bed traveling at 20 m/s relative to the highway rolls toward the back of the truck bed with a s
irga5000 [103]
14 m/s in the direction of the truck
5 0
3 years ago
# A cheetah can start from rest and attain the velocity 72km/h in 2 seconds. Calculate the acceleration of cheetah
yan [13]

Answer:

<h2>10 \: m/s ^2</h2><h2 />

Explanation:

Solution,

When a certain object comes in motion from rest, in the case, initial velocity = 0 m/s

Initial velocity ( u ) = 0 m/s

Final velocity ( v ) = 72 km/h ( Given)

We have to convert 72 km /h in m/s

72 \: km \: per \: hour

= 72 \times  \frac{1000}{60  \times 60}

= 20 m/s

Final velocity ( v ) = 20 m/s

Time taken ( t ) = 2 seconds

Acceleration (a) = ?

Now,

we have,

a =  \frac{v - u}{t}

a =  \frac{20 - 0}{2}

a =  \frac{20}{2}

a = 10 m/s ^2

Hope this helps...

Good luck on your assignment..

7 0
3 years ago
Paola can flex her legs from a bent position through a distance of 20.1 cm. Paola leaves the ground when her legs are straight,
makkiz [27]

The third equation of free fall can be applied to determine the acceleration. So that Paola's acceleration during the flight is 39.80 m/s^{2}.

Acceleration is a quantity that has a direct relationship with velocity and also inversely proportional to the time taken. It is a vector quantity.

To determine Paola's acceleration, the third equation of free fall is appropriate.

i.e V^{2} = U^{2} ± 2as

where: V is the final velocity, U is the initial velocity, a is the acceleration, and s is the distance covered.

From the given question, s = 20.1 cm (0.201 m), U = 4.0 m/s, V = 0.

So that since Poala flies against gravity, then we have:

V^{2} = U^{2} - 2as

0 = (4)^{2} - 2(a x 0.201)

  = 16 - 0.402a

0.402a = 16

a = \frac{16}{0.402}

  = 39.801

a = 39.80 m/s^{2}

Therefore Paola's acceleration is 39.80 m/s^{2}.

Visit: brainly.com/question/17493533

7 0
3 years ago
Read 2 more answers
A 78−kg skier is sliding down a ski slope at a constant velocity. The slope makes an angle of 21° above the horizontal direction
Feliz [49]

Answer:

274N 0.41

Explanation:

As he is sliding down in a constant speed then the force that accelerates him (weight) and the force that slows his down (friction) are equal.

then

<em>friction=mass x gravity x sin(21)</em>

Fr=78kg x 9.8m/s2 x sin(21)=274N

<em>friction= coefficient of kinetic friction x normal force of from the slope</em>

Fr= u x 78kg x 9.8m/s2 x cos(21)=274N

Fr= u x 78kg x 9.8m/s2 x cos(21)=274Nu=274/677=0.41

8 0
3 years ago
Compared to the thickness and density of the continental crust of South America, the oceanic crust of the Pacific floor is______
chubhunter [2.5K]

Answer:

The pacific floor (oceanic crust) is thinner and more denser

Explanation:

The continental crust have a thickness of about 35 to 40 km on an average, and are composed of rocks that has less denser granitic minerals such as feldspar, quartz.

On the other hand, the oceanic crust have a thickness of about 7 to 10 km on an average, and it is comprised of denser mafic rocks that contains high amount of olivine and pyroxene minerals.

Due to this, the oceanic crust subducts below the continental crust during the time of collision.

Thus, the pacific floor (oceanic crust) is thinner and more denser, in comparison to the South American continental crust.

3 0
3 years ago
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